Question

A certain quantity of a gas occupies 61.3 mLat 68◦C. If the pressure remains constant,what would the volume of the gas be at 17◦C?1. 52 mL2. 72 mL3. 32 mL4. 92 mL

Answer 1

Answer:

52 mL

Explanation:

Since the pressure of the gas remains constant, we can use the following gas law:

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where:

$V_1 = 61.3 mL=0.0613 L=0.0613 dm^3 = 6.13\cdot 10^{-5} m^3$ is the initial volume

$V_2 = ?$ is the final volume

$T_1 = 68^{\circ}C + 273=341 K$ is the initial temperature

$T_2 = 17^{\circ}C + 273=290 K$ is the final temperature

Substituting numbers and re-arranging the equation, we find the final volume of the gas:

$V_2=\frac{T_2}{T_1}V_1 = \frac{290 K}{341 K}(6.13\cdot 10^{-5} m^3)=5.21\cdot 10^{-5} m^3 = 52.1 mL$

So the correct answer is

1. 52 mL