All categories

1 year ago

If a bender can be used to bend 3/4-inch rmc, then it can also be used to bend__________emt.

Physics

1 answer:

USPshnik [31]1 year ago

3 0

A bender may also be used to bend 1-inch emt if it can bend 3/4-inch rmc.

<h3>A hand bender is what?</h3>

hand bender. a device with a diameter of no more than 1-1/4 in. that is used to bend EMT. To prevent crimping or flattening the conduit during bending, hand benders offer a radius that supports the conduit.

<h3>When would you utilize a hand bending device?</h3>

The user can produce very close bends with hockeys because they are 60% smaller than benders. Generally speaking, you should use a hand bender most of the time and reserve the hickey for when you need to create several really tight bends that a hand bender is unable to accomplish.

learn more about bender here

<u>brainly.com/question/9721733</u>

#SPJ4

You might be interested in

Which of the following statements is TRUE?

KIM [24]

Hello there!

<span>Which of the following statements is TRUE?

Correct answer: </span>Light waves are electromagnetic waves and sound waves are mechanical waves.

5 0

3 years ago

Read 2 more answers

A uniform electric field of magnitude 4.6 ✕ 104 N/C is perpendicular to a square sheet with sides 3.0 m long. What is the electr

rodikova [14]

Answer:

41.4* 10^4 N.m^2/C

Explanation:

given:

E= 4.6 * 10^4 N/C

electric field is 4.6 * 10^4 N/C and square sheet is perpendicular to electric field so, area of vector is parallel to electric field

then electric flux = ∫ E*n dA

= ∫ 4.6 * 10^4 * 3*3

= 41.4* 10^4 N.m^2/C

3 0

3 years ago

Read 2 more answers

A bird accelerating from rest at a constant rate,experiences a displacement of 28 m in 11s.What is its acceleration

Ksenya-84 [330]

Use the formula below for this question:

$v_{f} = v_{i} + 2 * a * d$

re-arrange to solve for a:

$a = \frac{v_{f} - v_{i}}{2 * d}$

now simply plug in your variables and there's your answer :). If you ever get stuck, you can look up the kinematic equations!

4 0

3 years ago

You stand on a frictional platform that is rotating at 1.8 rev/s. Your arms are outstretched, and you hold a heavy weight in eac

dusya [7]

Answer:

20.62361 rad/s

489.81804 J

Explanation:

$I_i$ = Initial moment of inertia = 9.3 kgm²

$I_f$ = Final moment of inertia = 5.1 kgm²

$\omega_i$ = Initial angular speed = 1.8 rev/s

$\omega_f$ = Final angular speed

As the angular momentum of the system is conserved

$I_i\omega_i=I_f\omega_f\\\Rightarrow \omega_f=\dfrac{I_i\omega_i}{I_f}\\\Rightarrow \omega_f=\dfrac{9.3\times 1.8}{5.1}\\\Rightarrow \omega_f=3.28235\ rev/s=3.28235\times 2\pi=20.62361\ rad/s$

The resulting angular speed of the platform is 20.62361 rad/s

Change in kinetic energy is given by

$\Delta K=\dfrac{1}{2}(I_f\omega_f^2-I_i\omega_i^2)\\\Rightarrow \Delta K=\dfrac{1}{2}(5.1\times (20.62361)^2-9.3\times (1.8\times 2\pi)^2)\\\Rightarrow \Delta K=489.81804\ J$

The change in kinetic energy of the system is 489.81804 J

As the work was done to move the weight in there was an increase in kinetic energy

6 0

2 years ago

Do thermohaline currents flow vertically or horizontally<br><br> A. Vertically<br> B. Horizontally

Shkiper50 [21]

B

M

‘’’’

Vujkbukbuvuvubkkbbiu

7 0

3 years ago