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AysviL [449]
3 years ago
14

The (nonconservative) force propelling a 1.50 × 103-kg car up a mountain road does 4.70 × 106 J of work on the car. The car star

ts from rest at sea level and has a speed of 27.0 m/s at an altitude of 2.00 × 102 m above sea level. Obtain the work done on the car by the combined forces of friction and air resistance, both of which are non conservative forces
Physics
1 answer:
aliina [53]3 years ago
6 0

Answer:

be the mehcanic for once and see what the answer is

Explanation:

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A bicycle tire has a radius of 0.23 m. the tire spins at a constant speed with a centripetal acceleration of 42 m/s2. what is th
vredina [299]

Answer:

a = v^2/r      centripetal acceleration

v = (a * r)^1/2 = (42 * .23)^1/2 = 3.1 m/s

3 0
2 years ago
Read 2 more answers
Which equations represent the relationship between wavelength and frequency for a sounds wave
ioda

   

Waves can be described using a number of different characteristics of a wave. Wavelength and frequency are two such characteristics. The relationship between wavelength and frequency is that the frequency of a wave multiplied by its wavelength gives the speed of the wave

6 0
3 years ago
If a net force of 100 N is applied to an object with a mass of 10 kg what will be the acceleration experienced by the mass? Show
dusya [7]

Explanation:

∑F = ma

100 N = (10 kg) a

a = 10 m/s²

3 0
4 years ago
When the valve between the 2.00-L bulb, in which the gas pressure is 2.00 atm, and the 3.00-L bulb, in which the gas pressure is
padilas [110]

Answer:

P_{C} = 3.2\, atm

Explanation:

Let assume that gases inside bulbs behave as an ideal gas and have the same temperature. Then, conditions of gases before and after valve opened are now modelled:

Bulb A (2 L, 2 atm) - Before opening:

P_{A} \cdot V_{A} = n_{A} \cdot R_{u} \cdot T

Bulb B (3 L, 4 atm) - Before opening:

P_{B} \cdot V_{B} = n_{B} \cdot R_{u} \cdot T

Bulbs A & B (5 L) - After opening:

P_{C} \cdot (V_{A} + V_{B}) = (n_{A} + n_{B})\cdot R_{u} \cdot T

After some algebraic manipulation, a formula for final pressure is derived:

P_{C} = \frac{P_{A}\cdot V_{A} + P_{B}\cdot V_{B}}{V_{A}+V_{B}}

And final pressure is obtained:

P_{C} = \frac{(2\,atm)\cdot (2\,L)+(4\,atm)\cdot(3\,L)}{5\,L}

P_{C} = 3.2\, atm

5 0
3 years ago
Because of friction, it required 6818.2 N to move a trailer 542 meters. How much work was accomplished?
nikklg [1K]

Answer:

The answer to your question is W = 3695464.4 J

Explanation:

Mechanical work is the force applied to an object multiply by the distance this object move as a consequence of the force.

Formula

Work = W (J)

Force = F (N)

distance = d (m)

                     W = F x d

Substitution

F = 6818.2 N

d = 542 m

                    W = 6818.2 x 542

Simplification and result

                    W = 3695464.4 J

5 0
3 years ago
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