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Assoli18 [71]
3 years ago
15

Which of the following is an intensive property?

Chemistry
2 answers:
Salsk061 [2.6K]3 years ago
7 0
A. Mass. And your welcome for helping u
PilotLPTM [1.2K]3 years ago
6 0
I believe the answer is A
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Which of the following statements is NOT correct?
Nutka1998 [239]

Answer:

I guess number three (3) Is wrong

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3 years ago
Most earthquakes occur along fractures in the Earth's crust called faults. Most faults occur along the edges of A) continents. B
Ahat [919]
Hey there!

The answer is C. Tectonic plates, with the most famous of earthquakes being a plate called the "Ring of Fire"  


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6 0
3 years ago
Read 2 more answers
Complete the equation for the dissociation of Na2CO3(aq).Omit water from the equation because it is understood to be present.
ozzi

Answer:

Na2CO3 <==> 2Na^+ + CO3^2-

Explanation:

6 0
2 years ago
How many moles of carbon, hydrogen, and oxygen are present in a 100-g sample of ascorbic acid?
Y_Kistochka [10]

There are:

3.41 moles of C

4.54 moles of H

3.40 moles of O.

Why?

To solve the problem, the first thing that we need to do is to write the chemical formula of the ascorbic acid.

C_{6}H_{8}O_{6}

Now, we know that there are 100 grams of the compound, so, the masses of each element will represent the percent in the compound.

We have that:

C_{6}=12.0107g*6=72.08g\\\\H_{8}=1.008g*8=8.064g\\\\O_{6}=15.999g*6=95.994g\\\\C_{6}H_{8}O_{6}=72.08g+8.064g+95.994g=176.138g

To know the percent of each element, we need to to the following:

C=\frac{72.08g}{176.138g}*100=0.409*100=40.92(percent)\\\\H=\frac{8.064g}{176.138g}*100=4.58(percent)\\\\O=\frac{95.994}{176.138g}*100=54.49(percent)

So, we know that for the 100 grams of the compound, there are:

40.92 grams of C

4.58 grams of H

54.49 grams of O

We know the molecular masses of each element:

C=12.0107\frac{g}{mol}\\\\H=1.008\frac{g}{mol}\\\\O=15.999\frac{g}{mol}{mol}

Now, to calculate the number of moles of each element, we need to divide the mass of each element by the molecular mass of each element:

C=\frac{40.92g}{12.010\frac{g}{mol}}=3.41mol\\\\H=\frac{4.58g}{1.008\frac{g}{mol}}=4.54mol\\\\O=\frac{54.49g}{15.999\frac{g}{mol}}=3.40mol

Hence, we have that there are 3.41 moles of C, 4.54 moles of H, and 3.40 moles of O.

Have a nice day!

5 0
3 years ago
Which of the following statements is a true statement regarding a solution with [H1+] =1x10-5 M and [OH1-]= 1x10-9 M?
zheka24 [161]

Answer:

B. The [H1+] >[OH1-] and the solution is acidic

4 0
2 years ago
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