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garik1379 [7]
2 years ago
6

The noble gases are located in which column of the periodic table?A. 1B. 6C. 9D. 18

Chemistry
1 answer:
Vika [28.1K]2 years ago
6 0
D IS THE ANSWER TO YOUR QUESTION
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An object with a density of 3.7kg/m^3 has a mass of 2.5g. What's the volume in mL?
valentinak56 [21]
d=3,7\frac{kg}{m^{3}}=3,7\frac{1000g}{1000000mL}=0,0037\frac{g}{mL}\\
m=2,5g\\\\
d=\frac{m}{V} \ \ |*V\\
dV=m \ \ |:d\\
V=\frac{m}{d}=\frac{2,5g}{0,0037\frac{g}{mL}}\approx 675,68mL
5 0
3 years ago
Select the correct answer.
Artist 52 [7]
I think c cause if he is in a relationship that’s abusive he needs to speak up before it goes way worst.
3 0
3 years ago
A gas mixture contains twice as many moles of o2 as n2. addition of 0.200 mol of argon to this mixture increases the pressure fr
pantera1 [17]
Number of moles of oxygen = x

number of moles of nitrogen = y

x = 2y

initial pressure, p1 = 0.8 atm

final pressure, p2 = 1.10 atm

At constant volume and temperature p1 / n1 = p2 / n2

=> p1 / p2 = n1 / n2

n1 = x + y = 2y + y = 3y

n2 = 0.2 + 3y

=> p1 / p2 = 3y / (0.2 + 3y)

=> 0.8 / 1.10 = 3y / (0.2 + 3y)

=> 0.8 (0.2 + 3y) = 1.10 (3y)

0.16 + 2.4y = 3.3y

=> 3.3y - 2.4y = 0.16

=> 0.9y = 0.16

=> y = 0.16 / 0.9

=. x = 2*0.16/0.9 = 0.356

Answer: 0.356 moles O2
8 0
3 years ago
How might the molecules inside an ice pack be different from the liquid inside of an insulated cup?​
MatroZZZ [7]

Answer:

The molecules inside the ice pack are frozen therefore they are stuck in place. The molecules inside an insulated cup aren't frozen but still stuck inside of their container so that they can not fly out.

Explanation:

5 0
3 years ago
The gas in an aerosol can is at a pressure of 3.16 atm at 32.2°C. What would the gas pressure in the can be at 22.9°C?
olasank [31]

Answer:

The pressure of the gas would be 3.06 atm

Explanation:

Amonton's law states that the pressure is directly proportional to the absolute temperature of a gas under constant volume. The equation is:

P1 / T1 = P2 / T2

<em>Where P1 is the initial pressure = 3.16atm</em>

<em>T1 is initial absolute temperature = 273.15 + 32.2°C = 305.35K</em>

<em>P2 is our incognite</em>

<em>And T2 is = 273.15 + 22.9°C = 296.05K</em>

<em />

Replacing:

3.16atm / 305.35K = P2 / 296.05K

3.06 atm = P2

<h3>The pressure of the gas would be 3.06 atm</h3>
5 0
3 years ago
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