Answer:

Explanation:
We want to convert from moles to grams, so we must use the molar mass. 
<h3>1. Molar Mass</h3>
The molar mass is the mass of 1 mole of a substance. It is the same as the atomic masses on the Periodic Table, but the units are grams per mole (g/mol) instead of atomic mass units (amu). 
We are given the compound PI₃ or phosphorus triiodide. Look up the molar masses of the individual elements. 
- Phosphorus (P): 30.973762 g/mol
- Iodine (I): 126.9045 g/mol 
Note that there is a subscript of 3 after the I in the formula. This means there are 3 moles of iodine in 1 mole of the compound PI₃. We should multiply iodine's molar mass by 3, then add phosphorus's molar mass. 
- I₃: 126.9045 * 3=380.7135 g/mol 
- PI₃: 30.973762 + 380.7135 = 411.687262 g/mol 
<h3>2. Convert Moles to Grams</h3>
Use the molar mass as a ratio.

We want to convert 3.14 moles to grams, so we multiply by that value. 

The units of moles of PI₃ cancel. 


<h3>3. Round</h3>
The original measurement of moles has 3 significant figures, so our answer must have the same. For the number we calculated, that is the tens place. 
The 2 in the ones place tells us to leave the 9. 

3.14 moles of phosphorous triiodide is approximately equal to <u>1290 grams of phosphorus triodide.</u>
 
        
             
        
        
        
Answer:
an organ system  Is a group of organs that work together to perform a com
Explanation:
that is the answer organ system 
now plz give me 5 stars and press on the heart plz 
 
        
             
        
        
        
Yes, because CO2 is carbon dioxide, and carbon dioxide contains molecules.
        
             
        
        
        
Answer:
The correct answer is option a.
Explanation:

Equilibrium concentration cadmium ions = ![[Cd^{2+}]=0.0585 M](https://tex.z-dn.net/?f=%5BCd%5E%7B2%2B%7D%5D%3D0.0585%20M)
 Equilibrium concentration fluoride ions = ![[F^{-}]=0.117 M](https://tex.z-dn.net/?f=%5BF%5E%7B-%7D%5D%3D0.117%20M)
Molar solubility is the maximum concentration of salt present in water in ionic form beyond that no more salt will exist in its ionic form and will settle down in bottom of the solution.
The molar solubility of the solid cadmium fluoride = 0.0585 M
 ..[1]
..[1]

Due to addition of sodium fluoride will increase concentration of fluoride in the solution.And due to common ion effect the equilibrium will shift in backward direction in [1], that is precipitation of more cadmium fluoride.
Hence, decrease in solubility will be observed.