All categories

3 years ago

What is the cosine if the sine=√5÷6

Mathematics

1 answer:

qwelly [4]3 years ago

7 0

Answer:

cosine = √31/6

Step-by-step explanation:

It is given that,

sine=√5/6

we know that, sine = opposite side/Hypotenuse

To find Adjacent side

Adjacent side = √(Hypotenuse² - opposite side²)

Adjacent side =√(6² - √5² ) = √(36 - 5 ) = √31

To find cosine

cosine = Adjacent side/Hypotenuse

cosine = √31/6

You might be interested in

Study the expression x-y+ z(x + y) Evaluate the expression if x = 10, y = -1, and z=0

vovangra [49]

Answer:

The value of the expression is 11

Step-by-step explanation:

Evaluate Expressions

An algebraic expression consists of a set of variables and constants related by algebraic operations like addition, subtraction, multiplication, etc.

To evaluate an algebraic expression, we replace the variables for the constant value they are assigned.

Let's consider the expression:

$x-y+ z(x + y)$

for x=10, y=-1, z=0

Substituting the variables for their values:

$10-(-1)+ (0)(10 -1)$

$=10+1+ (0)(9)$

$=11+0=11$

The value of the expression is 11

4 0

3 years ago

The volume of this prism

Licemer1 [7]

$answer = 66 \: {cm}^{3} \\ solution \\ volume = lwh \\ \: \: \: \: \: \: \: \: \: \: = \: 11 \times 3 \times 2 \\ \: \: \: \: \: \: \: \: \: = 66 \: {cm}^{3} \\ hope \: it \: helps \\ good \: luck \: on \: your \: assignment$

5 0

3 years ago

Read 2 more answers

When you (survive/accept) you get through something which is it idk

ValentinkaMS [17]

Survive because your persevering through a tough time

8 0

3 years ago

Read 2 more answers

Which of the following represents the cosine of 70 degrees

Westkost [7]

Using a calculator: cos 70 deg = 0.342. Note: it sounds as tho' you were given several answer options. Where are they?

6 0

3 years ago

64 POINT QUESTION √(5-2x) - √(2-x) = 1

Ivanshal [37]

Answer:

x = 2 and x = -2

Step-by-step explanation:

The easiest way is to guess. We know that you can't have a square root of a negative number. This constrains x between negative infinity to 2. Testing 2 and -2, we see that it satisfy the equation.

The more systematic approach is shown below

$\sqrt{5-2x}-\sqrt{2-x}=1 \\\sqrt{5-2x}-\sqrt{2-x}+\sqrt{2-x}=1+\sqrt{2-x} \\\sqrt{5-2x} = 1+\sqrt{2-x}$

$5-2x=(1+\sqrt{2-x})^2\\5-2x=1+2\sqrt{2-x}+2-x\\2-x=2\sqrt{2-x}\\1-0.5x=\sqrt{2-x}\\(1-0.5x)^2=2-x\\1-x+0.25x^2=2-x\\0.25x^2-1=0\\0.25x^2 = 1\\x^2 = 4\\x = +/-2$

x= -2, 2

7 0

3 years ago