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3 years ago

The reaction between 4-methyl-1-pentanol and pbr3 to yield 1-bromo-4-methylpentane is probably:

1 answer:

8 0

It is one of the topic in alcohol reaction and the answer is an SN2-type reaction involving the protonated alkyl dibomophosphite of the alcohol as the substrate. The reaction between 4-methyl-1-pentanol and PBr3to yield 1-bromo-4-methylpentane is probably an SN2-type reaction involving the protonated alkyl dibomophosphite of the alcohol as the substrate.

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To completely neutralise 200cm3 of 0.5mol/dm3 sodium hydroxide (NaOH), a student adds 100cm3 of 0.5mol/dm3 sulfuric acid (H2SO4)

OLga [1]

Answer:

0.1 mol

Explanation:

Step 1: Given data

Volume of the solution of sodium hydroxide (V): 200 cm³

Molar concentration of sodium hydroxide (C): 0.5 mol/dm³

Step 2: Convert "V" to dm³

We will use the conversion factor 1 dm³ = 1000 cm³.

200 cm³ × 1 dm³/1000 cm³ = 0.200 dm³

Step 3: Calculate the moles (n) of NaOH

The molarity of the NaOH solution is equal to the moles of NaOH divided by the volume of solution.

C = n/V

n = C × V

n = 0.5 mol/dm³ × 0.200 dm³ = 0.1 mol

6 0

3 years ago

If a 95.0 gram sample of metal at 100.0 oC is placed in 50.0 g of water with an initial temperature of 22.5oC and the final temp

kaheart [24]

Answer : The specific heat of the metal is, $1.11J/g^oC$

Explanation

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

$q_1=-q_2$

$m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)$

where,

$c_1$ = specific heat of metal = ?

$c_2$ = specific heat of water = $4.18J/g^oC$

$m_1$ = mass of metal = 95.0g

$m_2$ = mass of water = 50.0 g

$T_f$ = final temperature of mixture = $48.5^oC$

$T_1$ = initial temperature of metal = $100.0.0^oC$

$T_2$ = initial temperature of water = $22.5^oC$

Now put all the given values in the above formula, we get

$(95.0g)\times c_1\times (48.5-100.0)^oC=-[(50.0g)\times 4.18J/g^oC\times (48.5-22.5)^oC]$

$c_1=1.11J/g^oC$

Therefore, the specific heat of the metal is, $1.11J/g^oC$

8 0

3 years ago

An aqueous solution of sodium hydroxide is standardized by titration with a 0.198 M solution of perchloric acid. If 17.5 mL of b

baherus [9]

Answer:

The molarity of sodium hydroxide solution is 0.172 M

Explanation:

Step 1: Data given

Molarity of perchloric acid (HClO4) = 0.198 M

Volume of HClO4 = 15.2 mL = 0.0152 L

Volume of NaOH = 17.5 mL = 0.0175 L

Step 2: The balanced equation

HClO4 + NaOH → NaClO4 + H2O

Step 3: Calculate molarity of the sodium hydroxide solution

a*Cb*Vb = b*Ca*Va

⇒with a = the coefficient of HClO4 = 1

⇒with Cb = the molarity of NaOH = TO BE DETERMINED

⇒with Vb = the volume of NaOH = 0.0175 L

⇒with b = the coefficient of NaOH = 1

⇒with Ca = the molarity of HClO4 = 0.198 M

⇒with Va = the volume of HClO4 = 0.0152 L

Cb*0.0175 = 0.198 * 0.0152

Cb = 0.172 M

The molarity of sodium hydroxide solution is 0.172 M

5 0

3 years ago

How do you work out the moles of something?

Fittoniya [83]

1 mole of a pure substance has a mass equal to its molecular mass expressed in grams.
This is known as the molar mass, M, and has the units g mol-1
So 2 moles of a substance would have a mass = 2 x molar mass
3 moles of a substance would have a mass = 3 x molar mass etc
This leads to the formula: mass = moles x molar mass
If we let:
m = mass of substance in grams,
n = moles of pure substance,
M = molar mass of the pure substance in g mol-1
we can write the equation: m = n x M
This equation can be rearranged to give the following:
n = m ÷ M (moles = mass ÷ molar mass)
M = m ÷ n (molar mass = mass ÷ moles)

7 0

3 years ago

The speedometer in a car does not measure the car’s velocity because velocity is

dusya [7]

Answer:

because velocity is a vector quantity and has direction associated with it

Explanation:

6 0

3 years ago

Read 2 more answers