The reactants are oxygen and nitrogen monoxide.
<h3>What is nitrogen monoxide?</h3>
Nitrogen oxide, also known as nitrogen monoxide or nitric oxide, is an inert gas with the chemical formula NO. It is one of the main nitrogen oxides. Free radical nitric oxide (•N=O or •NO) possesses an unpaired electron, which is commonly indicated by a dot in its chemical formula. As a heteronuclear diatomic molecule, nitric oxide also contributed to the development of early modern theories of chemical bonding.
Nitric oxide is a chemical compound that occurs in combustion systems and can be produced by lightning during thunderstorms. It is a crucial intermediate in industrial chemistry. In many physiological and pathological processes in animals, including humans, nitric oxide serves as a signaling molecule.
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5.05 + 5 + 5.1 = 15.15cm Then you just divide it by the amount of measurements you had like this:15.15 ÷ 3 = 5.04999971cm Then you can just round it to the 3rd figure: 5.05cm < And that's the mean/average length of the bar. :) (Or the one above if you want all of the decimals too)
Answer:
Its pH value increases.
Explanation:
pH is the measure of alkalinity or acidity of a compound.
pH = - log [H+]
and pH + pOH = 14
where pOH is the measure of basicity of a solution, given by -log[OH-]
As a solution gets more basic that is higher [OH-], the pH increases, and on the other hand, as the pH of a solution decreases by one pH unit, the concentration of H+ increases by ten times.
<span>B)<span>C2H6O<span>2
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First, convert each percentage to grams: 38.7g, 9.70g, and 51.6g.
Next, calculate the number of moles of each element, based on the number of grams given.
C = 3.23 mol
H = 8.91 mol
O = 3.23 mol
Set up the ratio of moles of each element:
C3.34H9.70O3.23. Convert the decimals to whole numbers by dividing by the smallest subscript, 3.23.
The empirical formula is CH3O.
Now, compute the formula mass, which is 31. Finally, divide the molecular mass by the formula mass, 62/31 = 2. Multiple the subscripts by 2 to get the molecular formula.
