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sammy [17]
3 years ago
7

What is the ratio of carbon, hydrogen, and oxygen in most carbohydrates?

Chemistry
2 answers:
horrorfan [7]3 years ago
7 0
 In carbohydrates the C:H:O is 1:2:1
san4es73 [151]3 years ago
4 0

The ratio is— 1:2:1 (carbon, hydrogen, oxygen)

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If 6 moles of sugar was added to a kilogram of water, the new boiling point would be _____ degrees C.
Andru [333]
Using the equation for boiling point elevation Δt
     Δt = i Kb m 
we can find the new boiling point T for the solution:
     Δt = T - 100∘C 
since we know that pure water boils at 100 °C.

We know that the van't Hoff Factor i is equal to 1 because sugar does not dissociate in water.

Also, the value of Ebullioscopic constant Kb for water is listed as 0.512 °C·kg/mol.

The molality m of the solution of 6 moles of sugar dissolved in a kilogram of water can be calculated as 
     m = 6 moles / 1 kg
         = 6 mol/kg

Therefore the new boiling point T would be
     T - 100 °C = i Kb m 
     T = i Kb m + 100 °C.
        = (1) (0.512 °C·kg/mol) (6 mol/kg) + 100 °C
        = 3.072 °C + 100 °C 
        = 103.072 °C
3 0
3 years ago
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rewona [7]

Answer:

Decrease temperature with increase in ammonium nitrate concentration.

Explanation:

The temperature changes when different masses of ammonium nitrate are dissolved in water because the ammonium nitrate takes energy from the surrounding water environment for the breaking of ionic bonds as a result the temperature of water decreases. When more concentration of ammonium nitrate is added to water, more decrease occur in temperature of water and the water becomes cold.

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2 years ago
Question 7
Svet_ta [14]

Answer:

Check if the ions of two compounds exchange places.

Explanation:

The definition of single replacement is a reaction when an ion replaces another ion, thus the name.

7 0
3 years ago
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Using the thermodynamic information in the ALEKS Data tab, calculate the standard reaction entropy of the following chemical rea
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Answer:

ΔS° = - 47.2 J/mol.K

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∴ S°mH2O(l) = 69.9 J/mol.K

∴ S°mP4O10 = 231 J/mol.K

∴ S°mH3PO4 = 150.8 J/mol.K

⇒ ΔS° = 4*(150.8) - 6*(69.9) - 231

⇒ ΔS° = - 47.2 J/mol.K

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Analyses of enzymes found in the blood are used as indicators that tissue damage (heart, liver, muscle) has occurred and resulte
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Answer:

True.

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