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2 years ago

5

An atom that has lost or gained electrons is known as an ion. Which compound below is made up of ions?

2 answers:

nordsb [41]2 years ago

4 0

<h3>ANSWER:</h3>

(C) KBr

<h3>EXPLANATION:</h3>

An ionic compound is made up of a metal and a nonmetal. K is a metal while bromine is a nonmetal. Thus K transfers its one electron to bromine in order to form an ionic compound.

Alexus [3.1K]2 years ago

4 0

An ionic compound is composed of ions, a positive ion i.e. a cation and a negative ion i.e. an anion. The bond formed between the two elements is an ionic bond which is formed by the complete transfer of electrons from an electropositive element to the electronegative element. The electropositive element loses its electron and gains a positive charge whereas the electronegative atom accepts that electron and gains a negative charge.

In the given examples:

KBr is made up of ions

Potassium being electropositive becomes positively charged K+

Bromine is electronegative and becomes negatively charged Br-

KBr = K⁺Br⁻

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3 years ago

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$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

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Fractional abundance of $_{17}^{35}\textrm{Cl}$ isotope = x

<u>For $_{17}^{37}\textrm{Cl}$ isotope:</u>

Mass of $_{17}^{37}\textrm{Cl}$ isotope = 36.9659 amu

Fractional abundance of $_{17}^{37}\textrm{Cl}$ isotope = 1 - x

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Percentage abundance of $_{17}^{37}\textrm{Cl}$ isotope = $(1-0.7577)=0.2423\times 100=24.23\%$

Hence, the percentage abundance of $_{17}^{35}\textrm{Cl}$ and $_{17}^{37}\textrm{Cl}$ isotopes are 75.77% and 24.23% respectively.

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