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2 years ago

An atom that has lost or gained electrons is known as an ion. Which compound below is made up of ions?

Chemistry

2 answers:

nordsb [41]2 years ago

4 0

<h3>ANSWER:</h3>

<h3>EXPLANATION:</h3>

An ionic compound is made up of a metal and a nonmetal. K is a metal while bromine is a nonmetal. Thus K transfers its one electron to bromine in order to form an ionic compound.

Alexus [3.1K]2 years ago

4 0

An ionic compound is composed of ions, a positive ion i.e. a cation and a negative ion i.e. an anion. The bond formed between the two elements is an ionic bond which is formed by the complete transfer of electrons from an electropositive element to the electronegative element. The electropositive element loses its electron and gains a positive charge whereas the electronegative atom accepts that electron and gains a negative charge.

In the given examples:

KBr is made up of ions

Potassium being electropositive becomes positively charged K+

Bromine is electronegative and becomes negatively charged Br-

KBr = K⁺Br⁻

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2 years ago

9. To become like a noble gas the element P will have a charge of

MrRa [10]

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2 years ago

Consider the reaction. 2 Pb ( s ) + O 2 ( g ) ⟶ 2 PbO ( s ) An excess of oxygen reacts with 451.4 g of lead, forming 367.5 g of

Art [367]

Answer : The percent yield of the reaction is, 75.6 %

Solution : Given,

Mass of Pb = 451.4 g

Molar mass of Pb = 207 g/mole

Molar mass of PbO = 223 g/mole

First we have to calculate the moles of Pb.

$\text{ Moles of }Pb=\frac{\text{ Mass of }Pb}{\text{ Molar mass of }Pb}=\frac{451.4g}{207g/mole}=2.18moles$

Now we have to calculate the moles of $PbO$

The balanced chemical reaction is,

$2Pb(s)+O_2(g)\rightarrow 2PbO(s)$

From the reaction, we conclude that

As, 2 mole of $Pb$ react to give 2 mole of $PbO$

So, 2.18 mole of $Pb$ react to give 2.18 mole of $PbO$

Now we have to calculate the mass of $PbO$

$\text{ Mass of }PbO=\text{ Moles of }PbO\times \text{ Molar mass of }PbO$

$\text{ Mass of }PbO=(2.18moles)\times (223g/mole)=486.1g$

Theoretical yield of $PbO$ = 486.1 g

Experimental yield of $PbO$ = 367.5 g

Now we have to calculate the percent yield of the reaction.

$\% \text{ yield of the reaction}=\frac{\text{ Experimental yield of }PbO}{\text{ Theoretical yield of }PbO}\times 100$

$\% \text{ yield of the reaction}=\frac{367.5g}{486.1g}\times 100=75.6\%$

Therefore, the percent yield of the reaction is, 75.6 %

3 0

2 years ago

Nevermind, scratch the question

Lyrx [107]

What question there’s no question on here

5 0

1 year ago

How many grams of carbon dioxide are in 35.6 liters of co2

lina2011 [118]

The grams of carbon dioxide that are in 35.6 liters of Co2 is calculates as below
calculate the number of moles of CO2

At STP 1 mole = 22.4 L

what about 35.6 liters

= 1mole x 35.6 liters/ 22.4 liters = 1.589 moles

mass of CO2 = moles x molar mass of CO2

= 1.589 mol x 44 g/mol = 69.92 grams

3 0

2 years ago