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alexandr402 [8]
3 years ago
9

3 sources of background radiation and one source of radiation that is not condisderd background radiation

Chemistry
1 answer:
skad [1K]3 years ago
5 0
Natural sources. Natural sources of background radiation include: Cosmic rays - radiation that reaches the Earth from space. Rocks and soil - some rocks are radioactive and give offradioactive radon gas.
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Which family is most likely to form a 2+ ion?
inn [45]

I think the family of Group 2 metals are most likely to form a 2+ion.

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Which statement about the scientific veiws is correct?
hammer [34]
I think the answer will be b cuh
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4 years ago
How do I calculate the molecular weight of Mg(OH)2?
vodomira [7]

The molecular weight of Mg(OH)2 : 58 g/mol

<h3>Further explanation</h3>

Given

Mg(OH)2 compound

Required

The molecular weight

Solution

Relative atomic mass (Ar) of element : the average atomic mass of its isotopes  

Relative molecular weight (M)  : The sum of the relative atomic mass of Ar  

M AxBy = (x.Ar A + y. Ar B)  

So for Mg(OH)2 :

= Ar Mg + 2 x Ar O + 2 x Ar H

= 24 g/mol + 2 x 16 g/mol + 2 x 1 g/mol

= 24 + 32 + 2

= 58 g/mol

5 0
3 years ago
Consider the following reaction:
adell [148]

Answer:

1. d[H₂O₂]/dt = -6.6 × 10⁻³ mol·L⁻¹s⁻¹; d[H₂O]/dt = 6.6 × 10⁻³ mol·L⁻¹s⁻¹

2. 0.58 mol

Explanation:

1.Given ΔO₂/Δt…

    2H₂O₂     ⟶      2H₂O     +     O₂

-½d[H₂O₂]/dt = +½d[H₂O]/dt = d[O₂]/dt  

d[H₂O₂]/dt = -2d[O₂]/dt = -2 × 3.3 × 10⁻³ mol·L⁻¹s⁻¹ = -6.6 × 10⁻³mol·L⁻¹s⁻¹

 d[H₂O]/dt =  2d[O₂]/dt =  2 × 3.3 × 10⁻³ mol·L⁻¹s⁻¹ =  6.6 × 10⁻³mol·L⁻¹s⁻¹

2. Moles of O₂  

(a) Initial moles of H₂O₂

\text{Moles} = \text{1.5 L} \times \dfrac{\text{1.0 mol}}{\text{1 L}} = \text{1.5 mol }

(b) Final moles of H₂O₂

The concentration of H₂O₂ has dropped to 0.22 mol·L⁻¹.

\text{Moles} = \text{1.5 L} \times \dfrac{\text{0.22 mol}}{\text{1 L}} = \text{0.33 mol }

(c) Moles of H₂O₂ reacted

Moles reacted = 1.5 mol - 0.33 mol = 1.17 mol

(d) Moles of O₂ formed

\text{Moles of O}_{2} = \text{1.33 mol H$_{2}$O}_{2} \times \dfrac{\text{1 mol O}_{2}}{\text{2 mol H$_{2}$O}_{2}} = \textbf{0.58 mol O}_{2}\\\\\text{The amount of oxygen formed is $\large \boxed{\textbf{0.58 mol}}$}

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3 years ago
What biological processes can add co2 to the atmosphere?
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Cellar respiration simple if u need explanation just search up
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