Question

A teacher gave her class two exams; 60% of the class passed the second exam, but only 48% of the class passed both exams. What percent of those who passed the second exam also passed the first exam?

Answer 1

Should be 
0.48 / 0.60 = 0.80 = 80%

answer
80% passed the second exam also passed the first exam

Answer 2

Answer:

Percent of those who passed the second exam also passed the first exam = 80 %

Step-by-step explanation:

Let the number of students be 100.

We have 60% of the class passed the second exam

   Number of students passed the second exam$=\frac{60}{100}\times 100=60$

We also have

   Only 48% of the class passed both exams

   Number of students passed both exams$=\frac{4}{8100}\times 100=48$  

   Percent of those who passed the second exam also passed the first exam $=\frac{48}{60}\times 100=80 \%$