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Ainat [17]
3 years ago
10

In which region is the substance in both the solid phase and the liquid phase ?

Chemistry
2 answers:
olganol [36]3 years ago
4 0

Answer:

It's B) 2

Explanation:

just took quiz on e2020

Furkat [3]3 years ago
3 0
In which region is the substance in both the solid phase and the liquid phase ?
2
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Who goes to K12 and if so what grade
olchik [2.2K]

Answer:

I might next year with my cuz and nex year ima be in 8th

Explanation:

8 0
3 years ago
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For the following reaction, KcKc = 255 at 1000 KK.
bonufazy [111]

Answer :

The equilibrium concentration of CO is, 0.016 M

The equilibrium concentration of Cl₂ is, 0.034 M

The equilibrium concentration of COCl₂ is, 0.139 M

Explanation :

The given chemical reaction is:

                           CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)

Initial conc.      0.1550      0.173           0

At eqm.          (0.1550-x)  (0.173-x)         x

As we are given:

K_c=255

The expression for equilibrium constant is:

K_c=\frac{[COCl_2]}{[CO][Cl_2]}

Now put all the given values in this expression, we get:

255=\frac{(x)}{(0.1550-x)\times (0.173-x)}

x = 0.139 and x = 0.193

We are neglecting value of x = 0.193 because equilibrium concentration can not be more than initial concentration.

Thus, we are taking value of x = 0.139

The equilibrium concentration of CO = (0.1550-x) = (0.1550-0.139) = 0.016 M

The equilibrium concentration of Cl₂ = (0.173-x) = (0.173-0.139) = 0.034 M

The equilibrium concentration of COCl₂ = x = 0.139 M

5 0
3 years ago
Which element does not combine with sulfur? A.F B. G C. H D.K E. All can combine?
maw [93]
Answer is either B or all of the above. “G” is not an element on the periodic table. If it’s not a typo, then the answer is B.
8 0
4 years ago
Label the states of each compound in the reaction below.
devlian [24]

Answer:

CuSO₄(aq) + 2KOH (aq) —> Cu(OH)₂(s) + K₂SO₄(aq)

Explanation:

CuSO₄ + 2KOH —> Cu(OH)₂ + K₂SO₄

To know the state of each compounds, we shall determine the complete ionic equation. This can be obtained as follow:

In solution, CuSO₄ and KOH will dissociate as follow:

CuSO₄(aq) —> Cu²⁺(aq) + SO₄²¯(aq)

KOH (aq) —> K⁺ (aq) + OH¯(aq)

CuSO₄(aq) + KOH (aq) —>

Cu²⁺(aq) + SO₄²¯(aq) + 2K⁺(aq) + 2OH¯(aq) —> Cu(OH)₂(s) + 2K⁺(aq) + SO₄²¯(aq)

Note: Cu(OH)₂ is insoluble in water.

Therefore, the elemental equation is:

CuSO₄(aq) + 2KOH (aq) —> Cu(OH)₂(s) + K₂SO₄(aq)

8 0
3 years ago
The _______ is the area in which sediment is deposited along the shore. A. cove B. headland C. cave D. beach
Inessa05 [86]
The answer is d the beach
6 0
4 years ago
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