Answer:
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Explanation:
Answer :
The equilibrium concentration of CO is, 0.016 M
The equilibrium concentration of Cl₂ is, 0.034 M
The equilibrium concentration of COCl₂ is, 0.139 M
Explanation :
The given chemical reaction is:

Initial conc. 0.1550 0.173 0
At eqm. (0.1550-x) (0.173-x) x
As we are given:

The expression for equilibrium constant is:
![K_c=\frac{[COCl_2]}{[CO][Cl_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCOCl_2%5D%7D%7B%5BCO%5D%5BCl_2%5D%7D)
Now put all the given values in this expression, we get:

x = 0.139 and x = 0.193
We are neglecting value of x = 0.193 because equilibrium concentration can not be more than initial concentration.
Thus, we are taking value of x = 0.139
The equilibrium concentration of CO = (0.1550-x) = (0.1550-0.139) = 0.016 M
The equilibrium concentration of Cl₂ = (0.173-x) = (0.173-0.139) = 0.034 M
The equilibrium concentration of COCl₂ = x = 0.139 M
Answer is either B or all of the above. “G” is not an element on the periodic table. If it’s not a typo, then the answer is B.
Answer:
CuSO₄(aq) + 2KOH (aq) —> Cu(OH)₂(s) + K₂SO₄(aq)
Explanation:
CuSO₄ + 2KOH —> Cu(OH)₂ + K₂SO₄
To know the state of each compounds, we shall determine the complete ionic equation. This can be obtained as follow:
In solution, CuSO₄ and KOH will dissociate as follow:
CuSO₄(aq) —> Cu²⁺(aq) + SO₄²¯(aq)
KOH (aq) —> K⁺ (aq) + OH¯(aq)
CuSO₄(aq) + KOH (aq) —>
Cu²⁺(aq) + SO₄²¯(aq) + 2K⁺(aq) + 2OH¯(aq) —> Cu(OH)₂(s) + 2K⁺(aq) + SO₄²¯(aq)
Note: Cu(OH)₂ is insoluble in water.
Therefore, the elemental equation is:
CuSO₄(aq) + 2KOH (aq) —> Cu(OH)₂(s) + K₂SO₄(aq)