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Ainat [17]
3 years ago
10

In which region is the substance in both the solid phase and the liquid phase ?

Chemistry
2 answers:
olganol [36]3 years ago
4 0

Answer:

It's B) 2

Explanation:

just took quiz on e2020

Furkat [3]3 years ago
3 0
In which region is the substance in both the solid phase and the liquid phase ?
2
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Which statement about surfactant molecules is correct?
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Answer: c

Explanation: because the heads are hydrophobic and the tails are hydrophilic.estherefore they surfactant molecules containd both a water-insoluble(or oil-soluble)component.

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Identify the product of radioactive decay and classify the given nuclear reactions accordingly.
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Radioactive decay is the means by which unstable nuclei move towards stability by emitting energy and subatomic particles. The types are:

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8 0
3 years ago
Read 2 more answers
Lysozyme extracted from chicken egg white has a molar mass of 13,930 g mo1-1. Exactly 0.1 g of this protein is dissolved in 50 g
Natalija [7]

Answer:

Relative lowering in vapor pressure of solution is 23.7599 mmHg.

Depression in freezing point of the solution is 0.0002667 K.

Elevation in boiling point of the solution is 0.0000745 K.

Osmotic pressure of the solution is 0.0035 atm.

Explanation:

1) Relative lowering in vapor pressure of solution containing non volatile solute is equal to the mole fraction of the solute.

\frac{p^o-p_s}{p^o}=\frac{n_2}{n_1+n_2}

p^o= Vapor Pressure of the pure solvent

p_s= Vapor Pressure of the solution

n_2 moles of solute

n_1 = moles of solvent

Given; p^o=23.76 mmHg ,p_s=?

Moles of Lysozyme =n_2=\frac{0.1 g}{13,930 g/mol}=7.17\times 10^{-6} mol

Moles of water =n_1=\frac{50 g}{18 g/mol}=3.333 mol

\frac{23.76 mmHg-p_s}{23.76 mmHg}=\frac{7.17\times 10^{-6} mol}{3.333 mol+7.17\times 10^{-6} mol}

p_s=23.7599 mmHg

2) Depression in freezing point\Delta T_f is given by:

\Delta T_f=K_f\times m

K_f = molal depression constant of solvent

m = molality of the solution = \frac{moles}{\text{mass of solvent in kg}}

\Delta T_f=1.86 K kg/mol\times \frac{7.17\times 10^{-6} mol}{0.050 kg}

\Delta T_f=0.0002667 K

3) Elevation in boiling point\Delta T_b is given by:

\Delta T_b=K_b\times m

K_b = molal elevation constant of solvent

m = molality of the solution = \frac{moles}{\text{mass of solvent in kg}}

\Delta T_b=0.52 K kg/mol\times \frac{7.17\times 10^{-6} mol}{0.050 kg}

\Delta T_b=0.0000745 K

4) Osmotic pressure of the solution \pi is given as:

\pi =cRT

c = concentration of solution =\frac{Moles}{Volume(L)}

T = temperature of the solution

R = Universal gas constant = 0.0821 atm L/mol K

given , T = 298 K,

Mass of water = 50 g

Density of water = 1 g/ml

Volume of the water = \frac{50 g}{1 g/mL}=50 mL=0.050 L

c=\frac{7.17\times 10^{-6} mol}{0.050 L}

Since, there is less amount of solute in solvent volume of solution can be taken equal to the volume to the solution.

\pi =\frac{7.17\times 10^{-6} mol}{0.050 L}\times 0.0821 atm L/mol K\times 298 K

\pi=0.0035 atm

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How many significant figures<br> are in this number?<br> 107.051
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there are 6 significant figures in 107.051

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