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Ainat [17]
3 years ago
10

In which region is the substance in both the solid phase and the liquid phase ?

Chemistry
2 answers:
olganol [36]3 years ago
4 0

Answer:

It's B) 2

Explanation:

just took quiz on e2020

Furkat [3]3 years ago
3 0
In which region is the substance in both the solid phase and the liquid phase ?
2
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An aluminum ion has a charge of +3, and an oxide has a charge of -2. What would be the product of a reaction between these two e
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The product of a reaction between these two elements is Al_{2} O_{3}.

Explanation:

The oxidation state of an ion in a compound is equal to its charge.

The aluminum having a charge of +3 because oxidation state is +3

The oxide is having charge of -2

The product of these reactants will produce a chemical compound.

The compound formed is Al_{2} O_{3}  i.e Aluminium oxide. The compound while getting formed will share the charge and cation A+ will have the charge of anion and anion will have the charge of cation. This will result in a compound as there should be a neutral charge on the compound formed.

The <em>+</em><em>3 charge of the cation Al+ will go to anion oxide O2- and the charge of anion -2 will go with cation Al+. </em>

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3 years ago
4NaCl + 2SO2 + _____H2O + _____O2 → _____Na2SO4 + 4HCl
Alik [6]

The numbers that balance the following equation: 4NaCl + 2SO2 + H2O + O2 → Na2SO4 + 4HCl is 2, 1, 2.

BALANCING EQUATION:

  • Balancing a chemical equation means to make sure that the number of atoms of each element on both sides of the equation are equal.

  • According to this question, the following chemical reaction are given: 4NaCl + 2SO2 + H2O + O2 → Na2SO4 + 4HCl

  • Some of the coefficients (numbers) have been placed there while some are missing. The equation that includes the missing coefficients (numbers) to balance the equation is:

4NaCl + 2SO2 + 2H2O + O2 → 2Na2SO4 + 4HCl

Learn more at: brainly.com/question/21049751?referrer=searchResults

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You can form 9.20 L of NH₃ gas at 93.0 °C and 37.3 kPa or 2.56 L at STP. The balanced chemical equation is N₂ + 3H₂ → 2NH₃ Since all substances are gases, we can use litres instead of moles in our calculations. You don't specify the pressure and temperature of the NH₃, so I will calculate its volume in two ways. 
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