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2 years ago

In the force equation, which two variables have a direct relationship? Which two have an indirect/inverse relationship?

Chemistry

1 answer:

zhuklara [117]2 years ago

4 0

Answer:

if the dependent and independent variable go up its direct but if one of them goes up and another goes down its indirect

Explanation:

for example the more mass an object has the less speed it has that's indirect but the less salt you add to water the less time you have to wait for it to boil

i hope this was useful

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Why would a plant use the energy and resources to grow a fruit?

Step2247 [10]

Answer:

because a fruit holds the seeds it needs to reproduce and continue living.

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3 years ago

Which type of reaction occurs in the following equation?

Tems11 [23]

The type of reaction in above reaction is refered to as a disproportionation reaction .It sometimes used to describe desymmetrizing reaction.in the equation above compounds of intermediate oxidation state are converted to two different compound, that is Clo3 ions and 2cl-

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3 years ago

A cylinder of compressed gas has a volume of 350 ml and a pressure of 931 torr. What volume in Liters would the gas occupy if al

hodyreva [135]

Answer:

$0.384\ \text{L}$

Explanation:

$P_1$ = Initial pressure = 931 torr = $931\times \dfrac{101.325}{760}=124.12\ \text{kPa}$

$P_2$ = Final pressure = 113 kPa

$V_1$ = Initial volume = 350 mL

$V_2$ = Final volume

From the Boyle's law we have

$P_1V_1=P_2V_2\\\Rightarrow V_2=\dfrac{P_1V_1}{P_2}\\\Rightarrow V_2=\dfrac{124.12\times 350}{113}\\\Rightarrow V_2=384.44\ \text{mL}=0.384\ \text{L}$

The volume the gas would occupy is $0.384\ \text{L}$ .

3 0

2 years ago

The question is in the picture below

Rus_ich [418]

Answer:

$\Delta\text{H}_1+2\Delta\text{H}_2-\Delta\text{H}_3$

Explanation:

Hess's Law of Constant Heat Summation states that if a chemical equation can be written as the sum of several other chemical equations, the enthalpy change of the first chemical equation is equal to the sum of the enthalpy changes of the other chemical equations. Thus, the reaction that involves the conversion of reactant A to B, for example, has the same enthalpy change even if you convert A to C, before converting it to B. Regardless of how many steps it takes for the reactant to be converted to the product, the enthalpy change of the overall reaction is constant.

With Hess's Law in mind, let's see how A can be converted to 2C +E.

$\bf{\text{A} \rightarrow 2\text{B}}$ (Δ $\text{H}_1$ ) -----(1)

Since we have 2B, multiply the whole of II. by 2:

$\bf{2\text{B} \rightarrow 2\text{C} +2\text{D}}$ (2Δ $\text{H}_2$ ) -----(2)

This step converts all the B intermediates to 2C +2D. This means that the overall reaction at this stage is $\text{A} \rightarrow 2\text{C} +2\text{D}$ .

Reversing III. gives us a negative enthalpy change as such:

$\bf{2\text{D} \rightarrow \text{E}}$ (-Δ $\text{H}_3$ ) -----(3)

This step converts all the D intermediates formed from step (2) to E. This results in the overall equation of $\text{A} \rightarrow 2\text{C} +\text{E}$ , which is also the equation of interest.