Answer is: <span>concentration of NOCl is 3.52 M.
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Balanced chemical reaction: 2NOCl(g) ⇄ 2NO(g) + Cl₂<span>(g).
Kc = 8.0.
</span>[NOCl] = 1.00 M; equilibrium concentration.
[NO] = x.
[Cl₂] = x/2; equilibrium concentration of chlorine.<span>
Kc = </span>[Cl₂] ·[NO]² / [NOCl].
8.00 = x/2 · x² / 1.
x³/2 = 8.
x = ∛16.
x = 2.52 M.
co(NOCl) = [NOCl] + x.
co(NOCl) = 1.00 M + 2.52 M.
co(NOCl) = 3.52 M; the initial concentration of NOCl.
Answer:
Explanation:
rate of reaction
= -ve change in pressure of ethanol / time
= - (250 -237 )/100 = - 13 / 100 torr/s
= - 0.13 torr/s
next
- (237 - 224 )/100 = - 13 / 100 torr/s
= - .13 torr/s
next
- (224 - 211 )/100 = - 13 / 100 torr/s
= - .13 torr/s
so on
So rate of reaction is constant and it does not depend upon concentration or pressure of reactant .
So order of reaction is zero.
rate of reaction =K [C₂H₅OH]⁰
K is rate constant
K = .13 torr/s
In 900 s decrease in pressure
= 900 x .13 = 117
So after 900s , pressure of ethanol will be
250 - 117 = 133 torr
From the balanced equation:
<span>1mol C3H8 requires 5mol O2 for combustion </span>
<span>Molar mass C3H8 = 44g/mol </span>
<span>8.8g C3H8 = 8.8/44 = 0.2mol C3H8 </span>
<span>This will require 5*0.2 = 1.0mol O2 </span>
<span>Molar mass O2 = 32g/mol </span>
<span>Therefore 32g of O2 required.
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