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kumpel [21]
2 years ago
12

Reaction of ethylmagnesium bromide with which of the following compounds yields a primary alcohol after quenching with aqueous a

cid?
a. ethyl acetate
b. CH3CHO
c. (CH3)2CO
d. ethylene oxide
e. n- butyllithium
Chemistry
1 answer:
umka2103 [35]2 years ago
6 0

Answer

Option D

When a grignard Reagent reacts with Ethylene Oxide... A Primary Alcohol is Formed.

CH2OCH2 + RMgX ==> RCH2CH2OMgX

When You Hydrolyze

You have

RCH2CH2OH

The Text written below may come in handy someday.

Hope you find it helpful.

One of the preparation of Alcohols is via Reaction with "Grignard Reagents" .

Grignard Reagents have the formula "RMgX"

Where R is an alkyl group eg CH₃, C₂H₅ etc

X is a halogen eg Cl,Br etc

Ethylmagnesiumbromide fits the description of grignard Reagent from what I wrote above.

The formula for Ethylmagnesiumbromide is

"C₂H₅MgBr"

Now

When grignard reagents react with Alkanals... They form alcohols.

Note this trend.

When a grignard reagent reacts with Methanal(Formaldehyde)... It forms a Primary Alcohol.

When a grignard reagent reacts with any other Alkanal besides Methanal(formaldehyde) ... it forms Secondary Alcohols.

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Answer:

The temperature change from the combustion of the glucose is 6.097°C.

Explanation:

Benzoic acid;

Enthaply of combustion of benzoic acid = 3,228 kJ/mol

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Moles of benzoic acid = \frac{0.570 g}{122.12 g/mol}=0.004667 mol

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Q=3,228 kJ/mol \times 0.004667 mol=15.0668 kJ=15,066.8 J

Heat capacity of the calorimeter = C

Change in temperature of the calorimeter = ΔT = 2.053°C

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Enthaply of combustion of glucose= 2,780 kJ/mol.

Mass of glucose=2.900 g

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Energy released by the 0.016097 moles of calorimeter  combustion:

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Heat capacity of the calorimeter = C (calculated above)

Change in temperature of the calorimeter on combustion of glucose = ΔT'

Q'=C\times \Delta T'

44,749.1 J=7,338.92 J/^oC\times \Delta T'

\Delta T'=6.097^oC

The temperature change from the combustion of the glucose is 6.097°C.

6 0
2 years ago
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Explanation:

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