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zubka84 [21]
3 years ago
10

A light aircraft travels 2 miles per hour less than twice the speed of a van. If the van can travel 171 miles in the same time i

t takes the aircraft to travel 336 miles, then what is the average speed of each?
Physics
1 answer:
Gnom [1K]3 years ago
8 0

Answer:

The answers to the question are as follows

The average speed of the aircraft = 112 miles/hr and

the average speed of the van= 57 miles/hr

Explanation:

Speed of the van = X

Speed of the aircraft  = Y = 2 × X - 2 miles/hour

Distance covered by van  in time t = 171 miles

Distance covered by aircraft in time t = 336 miles

Therefore Y × t = 336 miles and

X × t = 171 miles

Therefore (2·X -2) × t = 336 miles

and  t = (171 miles)/X

(2·X -2) × (171 miles)/X  = 336 miles

(342·X-342)/X =336 → 6·X = 342

Therefore X = 57 miles/hour

and Y =2×57 -2 = 112 miles/hr

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What’s the dependent variable?
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Explanation:

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3 0
3 years ago
The intensity of a sound wave at a fixed distance from a speaker vibrating at 1.00 kHz is 0.750 W/m2. (a) Determine the intensit
sveticcg [70]

Answer:

a)   I = 3.63 W / m² , b)   I = 0.750 W / m²

Explanation:

The intensity of a sound wave is given by the relation

         I = P / A = ½ ρ v (2π f s_{max})²

         I = (½ ρ v 4π² s_{max}²) f²

a) with the initial condition let's call the intensity Io

        cte = (½ ρ v 4π² s_{max}²)

         I₀ = cte s² f₀²

        I₀ = cte 10 6

If frequency is increase f = 2.20 10³ Hz

         I = constant (2.20 10³) 2

         I = cte 4.84 10⁶

let's find the relationship of the two quantities

        I / Io = 4.84

        I = 4.84 Io

        I = 4.84 0.750

        I = 3.63 W / m²

b) in this case the frequency is reduced to f = 0.250 10³ Hz and the displacement s = 4 s or

        I = cte (f s)²

        I = constant (0.250 10³ 4)²

 

        I = cte 1 10⁶

         

the relationship

        I / Io = 1

        I = Io

        I = 0.750 W / m²

6 0
3 years ago
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