Answer:
{a universal set is a set which contains all objects, including itself}
Step-by-step explanation:
a) you will create two circle, crossing over each other, and shade both the "A" the "B" and the middle space.
b) (AUB) means the same thing as universal set, but its called union, infact if you draw this out in Venn Diagrams this will be the exact same as answer (a).
c) A n B : mean A 'intersection' with B, so here you will only shade the area where both circles meet.
d) i am not sure of this one, sorry
Three added to the product of four and twelve
Given: all selections are without replacement
Let D=event that chip is defective
N=event that chip is normal
note that D and N are complementary.
x=undefined event
(a) Second is defective
Probability for second chip to be defective
P(xD)=P(ND)+P(DD)
P(ND)=(80/100)*(20/99)=1600/9900
P(DD)=(20/100)*(19/99)=380/9900
=>
P(xD)=(1600+380)/9900=1980/9900=1/5
(b) All three are defective
P(DDD)=(20/100)*(19/99)*(18/98)=19/2695
Note: in probabilities, it is preferable to use the exact values (i.e. fractions).
Answer:
12 and 8
Step-by-step explanation:
The most reasonable estimate for 90 days is B. 2 × 
meals.
Explanation:
- The aircraft carrier can serve 1,633,500 meals over a period of 90 days.
- The given values are A. 2 ×
, B.2 × , C.2 × 
, D.2 × 
. All the given values are in the range of 2 so it will only logical if we round off the value we have too. We round off 1,633,500 to 2,000,000.
- Suppose you multiply 2 with 100 you get 100, 2 multiplied with 100 is represented by 2 ×
so the power to which 10 is raised represents the number of zeros in the resulting value i.e. 10 is raised to the power of 2 so the resulting answer has 2 zeroes.
- Options C and D have negative powers so they will equal decimal values so only options A and B could be the answer. Since there are 6 zeroes in 2,000,000 which is equal to 2 × . So the answer is option B.
