Do you have the answer choices ?
Calculate the pressure due to sea water as density*depth.
That is,
pressure = (1025 kg/m^3)*((9400 m)*(9.8 m/s^2) = 94423000 Pa = 94423 kPa
Atmospheric pressure is 101.3 kPa
Total pressure is 94423 + 101.3 = 94524 kPa (approx)
The area of the window is π(0.44 m)^2 = 0.6082 m^2
The force on the window is
(94524 kPa)*(0.6082 m^2) = 57489.7 kN = 57.5 MN approx
Answer:
The correct answer is
a) 1, 2, 3
Explanation:
In rolling down an inclined plane, the potential energy is Transferred to both linear and rotational kinetic energy thus
PE = KE or mgh = 1/2×m×v² + 1/2×I×ω²
The transformation equation fom potential to kinetic energy is =
m×g×h = ![\frac{1}{2} mv^{2} + \frac{1}{2} (\frac{2}{5} mr^{2} )(\frac{v}{r}) ^{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20mv%5E%7B2%7D%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20%28%5Cfrac%7B2%7D%7B5%7D%20mr%5E%7B2%7D%20%29%28%5Cfrac%7Bv%7D%7Br%7D%29%20%5E%7B2%7D)
= ![\sqrt{\frac{10}{7} gh}](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7B10%7D%7B7%7D%20gh%7D)
= ![\sqrt{gh}](https://tex.z-dn.net/?f=%5Csqrt%7Bgh%7D)
=![\sqrt{\frac{4}{3} gh}](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7B4%7D%7B3%7D%20gh%7D)
Therefore the order is with increasing rotational kinetic energy hence
the first is the sphere 1 followed by the disc 2 then the hoop 3
the correct order is a, 1, 2, 3
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Answer:
The answer is A
Explanation:
A large risk of tailgating is the collision avoidance time being much less than the driver reaction time. Driving instructors advocate that drivers always use the "two-second rule" regardless of speed or the type of road. During adverse weather, downhill slopes, or hazardous conditions such as black ice, it is important to maintain an even greater distance.