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Ulleksa [173]
3 years ago
9

Consider the energy diagram below. xn. mc012-1.jpg Which line indicates a higher reaction rate? A because it has a lower activat

ion energy. B because it has a lower activation energy. A because its mc012-2.jpgGrxn is much lower. B because its mc012-3.jpgGrxn is much lower.

Chemistry
2 answers:
matrenka [14]3 years ago
8 0

Answer:

b

Explanation:

34kurt3 years ago
5 0

Answer is: B because it has a lower activation energy.

For all chemical reaction some energy is required and that energy is called activation energy (energy that needs to be absorbed for a chemical reaction to start), activation energy for reaction B is lower that for reaction A.

Catalysis is the increase in the rate of a chemical reaction due to the participation of an additional substance called a catalyst.

Chemical reactions occur faster with a catalyst because they require less activation energy.

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Answer:

Explanation:

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3 0
3 years ago
For the following reaction, KcKc = 255 at 1000 KK.
bonufazy [111]

Answer :

The equilibrium concentration of CO is, 0.016 M

The equilibrium concentration of Cl₂ is, 0.034 M

The equilibrium concentration of COCl₂ is, 0.139 M

Explanation :

The given chemical reaction is:

                           CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)

Initial conc.      0.1550      0.173           0

At eqm.          (0.1550-x)  (0.173-x)         x

As we are given:

K_c=255

The expression for equilibrium constant is:

K_c=\frac{[COCl_2]}{[CO][Cl_2]}

Now put all the given values in this expression, we get:

255=\frac{(x)}{(0.1550-x)\times (0.173-x)}

x = 0.139 and x = 0.193

We are neglecting value of x = 0.193 because equilibrium concentration can not be more than initial concentration.

Thus, we are taking value of x = 0.139

The equilibrium concentration of CO = (0.1550-x) = (0.1550-0.139) = 0.016 M

The equilibrium concentration of Cl₂ = (0.173-x) = (0.173-0.139) = 0.034 M

The equilibrium concentration of COCl₂ = x = 0.139 M

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