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Ulleksa [173]
3 years ago
9

Consider the energy diagram below. xn. mc012-1.jpg Which line indicates a higher reaction rate? A because it has a lower activat

ion energy. B because it has a lower activation energy. A because its mc012-2.jpgGrxn is much lower. B because its mc012-3.jpgGrxn is much lower.

Chemistry
2 answers:
matrenka [14]3 years ago
8 0

Answer:

b

Explanation:

34kurt3 years ago
5 0

Answer is: B because it has a lower activation energy.

For all chemical reaction some energy is required and that energy is called activation energy (energy that needs to be absorbed for a chemical reaction to start), activation energy for reaction B is lower that for reaction A.

Catalysis is the increase in the rate of a chemical reaction due to the participation of an additional substance called a catalyst.

Chemical reactions occur faster with a catalyst because they require less activation energy.

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a) One kmol of N2O4 dissociates at 25℃, 1 atm to form an equilibrium ideal gas mixture of N2O4 and NO2 in which the amount of N2
horsena [70]

Answer:

neq N2O4 = 0.9795 mol.....P = 0.5 atm; T = 25°C

Explanation:

             ni      change    eq.

N2O4    1          1 - x       0.8154.....P = 1 atm; T = 25°C

NO2      0        0 + x          x

∴ x = neq = Peq.V / R.T.....ideal gas mix

if P = 0.5 atm, T = 25°C; assuming: V = 1 L

⇒ x = neq = ((0.5 atm)(1 L))/((0.082 atm.L/K.mol)(298 K))

⇒ x = neq = 0.0205 mol

⇒ neq N2O4 = 1 - x = 1 - 0.0205 = 0.9795 mol

3 0
3 years ago
Which of the following is a statement of Hess's law?
attashe74 [19]

Answer:

C

Explanation:

the enthalpy of reaction is independent of the reaction path

7 0
3 years ago
The recommended daily allowance (rda of calcium is 1.2 g. calcium carbonate contains 12.0% calcium by mass. how many grams of ca
defon
1) Calcium carbonate contains 40.0% calcium by weight.
M(CaCO₃)=100.1 g/mol
M(Ca)=40.1 g/mol
w(Ca)=40.1/100.1=0.400 (40.0%)!

2) Mass fraction of this is excessive data.

3) The solution is:

m(Ca)=1.2 g

m(CaCO₃)=M(CaCO₃)*m(Ca)/M(Ca)

m(CaCO₃)=100.1g/mol*1.2g/40.1g/mol=3.0 g
4 0
3 years ago
Read 2 more answers
Propane is often used to heat homes. The combustion of propane follows the following reaction: C3H8(g) + 5O2(g)  3CO2 (g) + 4H
swat32

Answer:

To release 7563 kJ of heat, we need to burn 163.17 grams of propane

Explanation:

<u>Step 1</u>: Data given

C3H8 + 5O2 -----------> 3CO2 + 4H2O      ΔH° = –2044 kJ

This means every mole C3H8

Every mole of C3H8 produces 2044 kJ of heat when it burns (ΔH° is negative because it's an exothermic reaction)

<u>Step 2: </u>Calculate the number of moles to produce 7563 kJ of heat

1 mol = 2044 kJ

x mol = 7563 kJ

x = 7563/2044 =  3.70 moles

To produce 7563 kJ of heat we have to burn 3.70 moles of C3H8

<u>Step 3: </u>Calculate mass of propane

Mass propane = moles * Molar mass

Mass propane = 3.70 moles * 44.1 g/mol

Mass propane = 163.17 grams

To release 7563 kJ of heat, we need to burn 163.17 grams of propane

7 0
3 years ago
I need someone to help with the bonus.
siniylev [52]

Answer:

268.3 m/sec

Explanation:

7 0
3 years ago
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