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3 years ago

Hypothesis

Chemistry

1 answer:

notsponge [240]3 years ago

8 0

Answer:

1) The problem is that you get a salty taste in our mouth when you drink orange juice after brushing our teeth.

Explanation:

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What is the actual yield if I reacted 100.0 g of uranium with excess bromine (uranium is the limiting reactant) and had an 83% y

rjkz [21]

Answer:

83 grams of uranium brainliest plz

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3 years ago

Q #4 please help if you are sure

Mashutka [201]

(Answer) (d) Chemical reaction rates vary with the conditions of the reaction, but nuclear decay rates do not.

Rate of a chemical reaction refers to rate of formation of products from reactions during a chemical reaction. The rates of chemical reactions depend on various factors such as temperature, pressure, concentration of reactants, presence of catalyst etc. For this reason, chemical reaction rates vary with the conditions of the reaction.

Nuclear decay rate refers to the constant ratio of the number of atoms of radioactive nucleus that decay during a certain interval of time to the total number of radioactive atoms at the beginning of the time interval. Nuclear decay rates are constant and do not vary with the conditions of the reaction.

8 0

3 years ago

If the reaction of 3.50 moles of lithium with excess hydrofluoric acid produced a 75.5% yield of hydrogen gas, what was the actu

melomori [17]

Answer: The correct answer is 1.32 mol $H_2$

Explanation:

For the reaction of lithium and hydrofluoric acid, the equation follows:

$2Li+2HF\rightarrow 2LiF+H_2$

By Stoichiometry of the reaction:

if 2 moles of lithium is producing 1 mole of hydrogen gas,

Then, 3.50 moles of lithium will produce = $\frac{1}{2}\times 3.5=1.75mol$ of hydrogen gas.

Now, to know the theoretical yield of hydrogen gas, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ...(1)

Moles of hydrogen gas = 1.75 mol

Molar mass of hydrogen gas = 2 g/mol

Putting values in above equation, we get:

$1.75mol=\frac{\text{Mass of hydrogen gas}}{2g/mol}\\\\\text{Given mass of hydrogen gas}=3.5gl$

To calculate the percentage yield, we use the equation:

$\%\text{ yield}=\frac{\text{Actual yield}}{\text{Theoretical yield}}\times 100$

Percentage yield = 75.5 %

Theoretical yield = 3.5 g

Putting values in above equation, we get:

$75.5=\frac{\text{actual yield}}{3.5g}\times 100\\\\\text{Actual yield}=2.64g$

Now, calculating the moles of hydrogen gas, we put the value in equation 1, we get:

$\text{Moles of hydrogen gas produced}=\frac{2.64g}{2g/mol}=1.32mol$

Hence, the correct answer is 1.32 mol $H_2$

5 0

3 years ago

Read 2 more answers

7. List all of the variables that you controlled or kept the same. Salt water

satela [25.4K]

Answer:

Temperature is a common type of controlled variable. If a temperature is held constant during an experiment, it is controlled. Other examples of controlled variables could be an amount of light, using the same type of glassware, constant humidity, or duration of an experiment.

Explanation:

3 0

3 years ago

8. A 220 mL sample of helium gas is in a cylinder with a movable piston at 105 kPa and 275K. The piston

Harrizon [31]

The sample has a new pressure of 274kPa. If at 105 kPa and 275K, a 220 mL sample of helium gas is contained in a cylinder with a moving piston. The sample is pushed till it has a 95.0 mL volume and 310K .

The macroscopic characteristics of ideal gases are related by the ideal gas law (PV = nRT). A gas is considered to be perfect if its particles (a) do not interact with one another and (b) occupy no space (have no volume). Where P= pressure V= volume and T = temperature.

From ideal gas equation

P₁V₁/T₁ =P₂V₂/T₂

105×220÷275 = P₂ ×95÷310

P₂= (105×220×310)÷(275×95)

P2= 7161000/26125

P2 = 274.105 kPa

Hence, the new pressure of helium gas is 274kPa

To know more about Ideas gas equation

brainly.com/question/28837405

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8 0

1 year ago