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dalvyx [7]
3 years ago
7

How many moles of nitrogen are in 1 mole of Al(NO3)3?

Chemistry
1 answer:
Molodets [167]3 years ago
7 0

Answer:

c i think

Explanation:

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A 1.044 g sample contains only vitamin C (C6H8O6) and sucralose (C12H19Cl3O8). When the sample is dissolved in water to a total
Strike441 [17]

Answer:

1.044 g sample contains only vitamin C (C6H8O6) and sucralose (C12H19Cl3O8). When the sample is dissolved in water to a total volume of 33.0 mL, the osmotic pressure of the solution is 3.69 atm at 295 K.

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3 years ago
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When carbon an oxygen combine chemically, the mass of the product is....
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It should be equal to the mass of the carbon plus the mass of the oxygen. This is because of the conservation of mass law. Mass is never created or destroyed only conserved. Hope this helped
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3 years ago
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Determine the number of moles of air present in 1.35 L at 750 torr and 17.0°C. Which equation should you use? COMPLETE What is t
xxTIMURxx [149]

Answer:

0.0559 mol

Explanation:

Step 1: Given and required data

  • Volume of air (V): 1.35 L
  • Pressure of air (P): 750 torr
  • Temperature (T): 17.0 °C
  • Ideal gas constant (R): 0.0821 atm.L/mol.K

Step 2: Convert "P" to atm

We will use the conversion factor 1 atm = 760 torr.

750 torr × 1 atm/760 torr = 0.987 atm

Step 3: Convert "T" to Kelvin

We will use the following expression.

K = °C + 273.15

K = 17.0 °C + 273.15 = 290.2 K

Step 4: Calculate the number of moles of air

If we assume air behaves as an ideal gas, we can calculate the moles (n) of air using the ideal gas equation.

P × V = n × R × T

n = P × V/R × T

n = 0.987 atm × 1.35 L/(0.0821 atm.L/mol.K) × 290.2 K = 0.0559 mol

4 0
3 years ago
1. A student combined silver nitrate and sodium
Tcecarenko [31]

Answer:

150.08 g

Explanation:

According the law of conservation of mass, mass can neither be created nor destroyed but is converted from one form to another.

As a result of this, the total mass of reactants must be equal to the total mass of products.

If this is so, we have been told that the mass of AgCl is 150.15 g, the total mass of products is 300.23g.

Therefore; mass of NaNO3 = 300.23 g - 150.15 g = 150.08 g

6 0
3 years ago
WILL MARK BRAINLIEST!!!
Ludmilka [50]
The answer is 1 x10^-10
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3 years ago
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