Answer:
v = 384km/min
Explanation:
In order to calculate the speed of the Hubble space telescope, you first calculate the distance that Hubble travels for one orbit.
You know that 37000 times the orbit of Hubble are 1,280,000,000 km. Then, for one orbit you have:

You know that one orbit is completed by Hubble on 90 min. You use the following formula to calculate the speed:

hence, the speed of the Hubble is approximately 384km/min
Answer:
Explanation:
As the source is situated on x - axis , it must be situated in between the two listeners .
So the x coordinate of source is
(-7 + 3 )/2
= - 2 m
The equation of the wave- front will be that o a circle having centre at (-2,0)
and radius = distance between -2 and 3 , that is 5 m
equation of circle
=( x+2 )² + y² = 25
It cuts y axis when x = 0
Putting x = 0
4 + y² = 25
y² = 21
y = + √21 , or - √21
Answer:
734.16 kg m/
Explanation:
The problem is asking for the Force of pushing off the ground.
- The formula of Force is: F = mass x acceleration
Given = <em>Mass</em>: 600 newtons (N)
<em>Acceleration</em>: 12 m/
We have to convert the mass into kg first. Remember that <u>1 kg is equal to 9.80665 newtons.</u>
Let x be the<em> mass in newtons</em>.
Let's convert:
x
=
= 61.18 kg
Phil's weight is 61.18 kg
Let's go back to finding the force.
F = m x a
F = 61.18 kg x 12 m/
F = 734.16 kg m/