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4 years ago

What happens to a gas when its temperature decreases?

2 answers:

7 0

When the temperature of a jar of gas decreases the pressure of the gas also decreases. The volume remains constant. Gas always fills whatever container it is in.

TiliK225 [7]4 years ago

6 0

Hey There!

When the gas temperature decreases the volume decreases too.

Thank You!

Have a question? Need Support? Feel free to message me.

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A train travelled from city a to city b. For the first 14hours,it travelled at an average speed of 120km/h. For the 10 hours, it

Nataly [62]

Explanation:

distance covered in the first part of journey : 120×14 = 1680km

distance covered in second part of journey :

90×10 = 900 km

total distance traveled : 1680+900 = 2580km.

total time taken to complete the journey : 14+10= 24 hrs.

therefore, the average speed of the journey = 2580km/24hr = 107.5 km/h.

hope this helps you.

4 0

3 years ago

The weight of a person on Earth is 67.0 N. If the gravitational acceleration on the moon is 1.62 m/s2, calculate the person’s we

Rzqust [24]

Answer:

$\large{ \boxed{ \tt{b) \: 11.0 \: N}}}$

- Please see the attached picture for full solution!:)

--------------- HappY LearninG <3 ---------

5 0

2 years ago

Which of the following best describe the particles in a liquid.

VashaNatasha [74]

A. fixed volume, changeable shape.

4 0

3 years ago

On a sunny day, as the distance from your hand to the ground increases, the shadow of your hand on the ground become fuzzier bec

USPshnik [31]

Answer:

the Sun is a circle in the sky and that creates a penumbra

Explanation:

A penumbra is basically a lighter and hazy outer part of the shadow. It is the partially shaded portion of the outer region of a shadow that is cast by an opaque object.

In the context, as the distance from the hand to the surface of the ground increases on a sunny day, the shadow of the hand that falls on the ground becomes fuzzier because the sun is an opaque object in the sky and it creates a penumbra which makes the shadow of the hand on the ground fuzzier as the distance is increased.

4 0

3 years ago

Calculate the escape speed for a spacecraft from the surface of (a) mars; and from the surface of (b) jupiter. ( the escape spee

Len [333]

The escape speed for a spacecraft at the surface of a planet of mass M and radius R is:
$v= \sqrt{ \frac{2GM}{R} }$
where G is the gravitational constant. We can use this formula to solve both parts of the problem, using the data of Jupiter and Mars.

a) Mars:
Mars mass is $M=6.4 \cdot 10^{24}kg$ , while Mars radius is $R=3.4 \cdot 10^6 m$ , so the escape speed of the spacecraft at Mars surface is
$v= \sqrt{ \frac{2 (6.67 \cdot 10^{-11} m^3 kg^{-1} s^{-2})(6.4 \cdot 10^{24} kg)}{3.4 \cdot 10^6 m} }= 5011 m/s = 5.01 km/s$

b) Jupiter:
Jupiter mass is $M=1.9 \cdot 10^{27} kg$ while its radius is $R=7.15 \cdot 10^7 m$ , so the escape speed at its surface is
$v= \sqrt{ \frac{2 (6.67 \cdot 10^{-11} m^3 kg^{-1}s^{-2})(1.9 \cdot 10^{27} kg)}{7.15 \cdot 10^7 m} }=5.95 \cdot 10^4 m/s = 59.5 km/s$

3 0

4 years ago