1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
larisa [96]
2 years ago
15

A wooden beam with a mass of 10.8 kg is supported by vertical supports

Physics
1 answer:
blondinia [14]2 years ago
7 0

Answer:

Force from the support closest = 79.8 N

Force from the support furthest = 61.9 N

Explanation:

Let's say the length of the beam is L.  Let's say A is the near end of the beam and B is the far end of the beam.

Draw a free body diagram.  There are four forces on the beam:

Reaction force Ra at the near end (0),

Reaction force Rb at the far end (L),

Weight force of the beam Mg at the center (L/2),

Weight force of the book mg at L/4 from A.

Sum of torques at A:

∑τ = Iα

Rb (L) − Mg (L/2) − mg (L/4) = 0

Rb (L) = Mg (L/2) + mg (L/4)

Rb = ½ Mg + ¼ mg

Rb = (½ M + ¼ m) g

Rb = (½ (10.8 kg) + ¼ (3.66 kg)) (9.8 m/s²)

Rb = 61.9 N

Sum of forces in the y direction:

∑F = ma

Ra + Rb − Mg − mg = 0

Ra = Mg + mg − Rb

Ra = (M + m) g − Rb

Ra = (10.8 kg + 3.66 kg) (9.8 m/s²) − 61.9 N

Ra = 79.8 N

You might be interested in
A 190 g air-track glider is attached to a spring. The glider is pushed in 8.6 cm against the spring, then released. A student wi
spin [16.1K]

Answer:

The spring constant = 9.25 N/m

Explanation:

The equation of an object attached to a spring that is oscillating is

T = 2π√(m/k)

Where T = period of the oscillation, m = mass of the object, k = spring constant.

Making k the subject of the equation,

k = 4π²m/T²......................... Equation 1

Note: Period(T) is the time taken to complete one oscillation

Given: T = t/10 = 9.0/10 = 0.9 s, m = 190 g = 0.19 kg.

Constant:  π = 3.14

Substitute these values into equation 1.

k = 4(3.14)²(0.19)/0.9²

k = 7.4933/0.81

k = 9.25 N/m

Thus the spring constant = 9.25 N/m

5 0
2 years ago
A ball of mass 4.5 kg moving with speed of 2.2 m/s in the +x-direction hits a wall and bounces back with the same speed in the x
Levart [38]

Answer:

The change of the momentum of the ball is -19.8\, \frac{mkg}{s}

Explanation:

We should find \varDelta\overrightarrow{p}=\overrightarrow{p_{f}}-\overrightarrow{p_{i}} (1)with \overrightarrow{p_{i}} the initial momentum and \overrightarrow{p_{f}} the final momentum. Linear momentum is defined as \overrightarrow{p}=m\overrightarrow{v}, using that on (1):

\varDelta\overrightarrow{p}=m \overrightarrow{v_{f}}-m \overrightarrow{v_{i}} (2)

It's important to note that momentum and velocity are vectors and direction matters, so if +x direction is the direction towards the wall and the -x direction away the wall \overrightarrow{v_{i}}=+2.2\, \frac{m}{s} and \overrightarrow{v_{f}}=-2.2\, \frac{m}{s} so (2) becomes:

\varDelta\overrightarrow{p}=m(-2.2- (+2.2))=-(4.5)(4.4)

\varDelta\overrightarrow{p}=-19.8\, \frac{mkg}{s}

8 0
3 years ago
A 1.1-kg object is suspended from a vertical spring whose spring constant is 120 N/m. (a) Find the amount by which the spring is
andriy [413]

Answer:

e = 0.0898m

v = 2.07m/s

Explanation:

a) According to Hooke's law

F = ke

e is the extension

k is the spring constant

Since F = mg

mg = ke

e = mg/k

Substitute the given value

e = 1.1(9.8)/120

e = 10.78/120

e = 0.0898m

Hence it is stretched by 0.0898m from its unstrained length

2) Total Energy = PE+KE+Elastic potential

Total Energy = mgh +1/2mv²+1/2ke²

Substitute the given value

5.0= 1.1(9.8)(0.2)+1/2(1.1)v²+1/2(120)(0.0898)²

Solve for v

5.0 = 2.156+0.55v²+0.48338

5.0-2.156-0.48338= 0.55v²

2.36 =0.55v²

v² = 2.36/0.55

v² = 4.29

v ,= √4.29

v = 2.07m/s

Hence the required velocity is 9.28m/s

4 0
3 years ago
A car races around a circular track. Friction on the tires is the what that acts toward the center of the circle and keeps the c
Ivanshal [37]
I would think force. Because friction has to have force to work ^-^
8 0
3 years ago
A computational model predicts the maximum kinetic energy a roller coaster car can have given its mass, the speed at the highest
Ymorist [56]

Answer:

D

Explanation:

The decrease in potential energy is equal to the increase in kinetic energy.

mgh

250 x 9.8 x 30

=73, 500

3 0
2 years ago
Other questions:
  • An apple drops from a tree and hits the ground in 1.5s what is its speed just before it hits the ground?
    11·1 answer
  • The product of an object’s mass and velocity
    11·2 answers
  • The current supplied to an air conditioner unit is 2.54 amps. The air conditioner is wired using a 10-gauge (diameter 2.588 mm)
    8·1 answer
  • PLEASE HELP ME
    7·1 answer
  • A motorcyclist is making an electric vest that, when connected to the motorcycle's 12 V battery, will warm her on cold rides. Sh
    10·1 answer
  • Hi im in class and i need help!
    6·2 answers
  • A cave rescue team lifts an injured spelunker directly upward and out of a sinkhole by means of a motor-driven cable. The lift i
    7·1 answer
  • A car slows down from 21 m/s to rest in a distance of 63m. Assuming the car has a constant acceleration, calculate the time it t
    12·1 answer
  • As best you can, describe how we can tell the age of the Earth and rocks found on it.
    7·1 answer
  • Which statement about the photoelectric effect is true?
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!