How long does it take a 5kW shower to use 25000J of energy?

How does an increase in greenhouse gases in the atmosphere cause an increase in global temperature?

daser333 [38]

Answer:

<h2>Greenhouse gases absorb and emit radiation and less heat dissipates to space</h2>

Explanation:

when heat is trapped it is conducted to the trapped area and gradually heats up its surrounding

8 0

3 years ago

Air trapped in the fur of the caribou’s coat functions as _____.

ioda

It functions as insulation, to keep it warm

5 0

3 years ago

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An object moves in a straight path. Its position x as a function of time t is presented by the equation x(t) = at – bt2+c, where

ankoles [38]

Answer:

The answer is below

Explanation:

Given that:

x(t) = at – bt2+c

a) x(t) = at – bt2+c

Substituting a = 1.4 m/s, b = 0.06 m/s2 and c =50 m gives:

x(t) = 1.4t - 0.06t² + 50

At t = 5, x(5) = 1.4(5) - 0.06(5)² + 50 = 55.5 m

At t = 0, x(0) = 1.4(0) - 0.06(0)² + 50 = 50 m

The average velocity (v) is given as:

$v=\frac{x(5)-x(0)}{5-0}\\ \\v=\frac{55.5-50}{5-0}=1.1\\ \\v=1.1\ m/s$

b) x(t) = 1.4t - 0.06t² + 50

At t = 10, x(10) = 1.4(10) - 0.06(10)² + 50 = 58 m

At t = 0, x(0) = 1.4(0) - 0.06(0)² + 50 = 50 m

The average velocity (v) is given as:

$v=\frac{x(10)-x(0)}{10-0}\\ \\v=\frac{58-50}{10-0}=0.8\\ \\v=0.8\ m/s$

c) x(t) = 1.4t - 0.06t² + 50

At t = 15, x(5) = 1.4(15) - 0.06(15)² + 50 = 57.5 m

At t = 10, x(10) = 1.4(10) - 0.06(10)² + 50 = 58 m

The average velocity (v) is given as:

$v=\frac{x(15)-x(10)}{15-10}\\ \\v=\frac{57.5-58}{15-10}=0.1\\ \\v=0.1\ m/s$

6 0

3 years ago

¿Porque los sensores son importantes en nuestra vida diaria?

7nadin3 [17]

En la medicina y la biotecnología, los sensores son herramientas que detectan procesos biológicos, químicos, o físicos y luego transmiten o reportan esta información. Algunos sensores trabajan fuera del cuerpo, mientras que otros están diseñados para ser implantados dentro del cuerpo.

Algunos dispositivos de monitoreo constan de múltiples sensores que miden una serie de parámetros físicos o biológicos. Otros dispositivos pueden ser multifuncionales, incorporando sensores y luego suministrando un fármaco o intervención en base a la información obtenida de los sensores. Los sensores pueden ser también componentes en sistemas que procesan muestras clínicas, tales como los dispositivos cada vez más comunes conocidos como “lab-on-a-chip”.

Los sensores ayudan a los proveedores del cuidado de la salud y a los pacientes a monitorear las condiciones de la salud y asegurar que puedan tomar decisiones informadas sobre el tratamiento. Los sensores también se utilizan a menudo para monitorear la seguridad de los medicamentos, los alimentos, las condiciones ambientales, y otras sustancias que podríamos encontrar.

8 0

3 years ago

1. A fluid with viscosity 1.2 Pa s moves through a 200-m-long pipe with a 20 cm diameter. What difference in pressure between th

Helen [10]

(1) The difference in pressure between the ends of the pipe is 611 kPa.

(2) The Reynold's number for this torpedo is 1.2 x 10⁷.

(3) The flow of water around the torpedo is turbulent.

<h3>Difference in pressure between the ends of the pipe</h3>

The difference in pressure is calculated by applying Poiseuille formula.

$V = \frac{\pi \Delta P r^4 t}{8\eta L} \\\\\frac{V}{t} = \frac{\pi \Delta P r^4 }{8\eta L}\\\\Q = \frac{\pi \Delta P r^4 }{8\eta L}$

where;

Q is flow rate
r is radius of the pipe
L is length of the pipe
η is viscosity
ΔP is change in pressure

$\Delta P = \frac{8Q\eta L}{\pi r^4}$

$\Delta P = \frac{8(0.1)(1.2)(200)}{\pi (0.1)^4} \\\\\Delta P = 611,155 \ Pa\\\\\Delta P \approx 611 \ kPa$

<h3>Reynold's number for the torpedo</h3>

$Re = \frac{Vl \rho }{\mu} \\\\Re = \frac{(10)(1.2)(1000)}{1 \times 10^{-3}} \\\\Re = 1.2 \times 10^7$

<h3>Laminar or turbulent flow </h3>

A flow is considered laminar if the Reynolds number is up to 2300.
A flow is considered turbulent if the Reynolds number is greater than 3500.

The calculated Reynold's number (1.2 x 10⁷) is greater than 3500. Thus, the flow is turbulent.

Learn more about turbulent flow here: brainly.com/question/12081428

#SPJ1

8 0

2 years ago