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emmainna [20.7K]
3 years ago
7

Why do you think the Combination Square is better to use than the tape

Engineering
1 answer:
Tatiana [17]3 years ago
8 0

Answer:

The correct answer to the following question will be "Because the head acts as a stop".

Explanation:

  • Since the head serves as either a stopping (especially in comparison to something like a floppy tape clip or hanger), the combination square seems to be more reliable and accurate than those of the tape measure.
  • And maybe you'll know that certain style outlines are still square to something like the sides or finishes.

So that the above seems to be the right answer.

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What are the common approximations made in the analysis of heat exchangers?
Oksanka [162]

Answer: making sure that they are up to date

Explanation:

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3 years ago
Which of the following material properties varies with temperature? a)- density b)- viscosity c)- electrical resistance d)- all
Reil [10]

Answer:

(d) all of the above

Explanation:

Effect on the density of temperature: If we increase the temperature of any room then particles of the room moves and to and fro and so density is decrease

Effect on the viscosity  of temperature : viscosity is inversely proportional to the temperature if we increase the temperature viscosity decreases and if we decrease the temperature viscosity increases.

Effect on the resistance of temperature : For metals if we increase the temperature then resistance increases and for semiconductor if we increase the temperature resistance decreases

So from above discussion all the parameter depends on the temperature so option (d( will be the correct option  

6 0
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List five pieces of personal safety equipment which must be in everyday use in the workshop​
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Answer:

safety glasses, hearing protection, respirator, work gloves, and work boots.

Explanation:

please give brainliest!! <3

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3 years ago
If the same amount of force were applied to all four balls in the picture, which would experience the greatest change in motion?
nydimaria [60]
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6 0
3 years ago
Read 2 more answers
Calculate KI for a rectangular bar containing an edge crack loaded in three-point bending where P=35.0 kN, W=50.8 mm, B=25 mm, a
Katyanochek1 [597]

Answer:

K_{I}=5.21 MPa\sqrt{m}

Explanation:

given data

Load P = 35 kN

Width of bar W = 50.8 mm

Breadth of bar B = 25 mm

Ratio of crack length to width α = a/W = 0.2

solution

we get here KI for a rectangular bar that is express as

K_{I} = \frac{6P}{BW}Y\sqrt{\pi a}   ................................1

here Y is the geometrical function

so

Y = \frac{1.12+\alpha (3.43\alpha -1.89)}{1-0.55\alpha}

Y = \frac{1.12+0.2(3.43\times 0.2-1.89)}{1-0.55\times 0.2}  

Y = \frac{0.8792}{0.89}  

Y = 0.9878

so put here value in equation 1

K_{I} = \frac{6\times 35\times 10^{3}}{0.025\times 0.0508}\times 0.9878\times \sqrt{3.1415\times (0.2\times 0.0508)}    

K_{I} = 165354.33\times 10^{3}\times 0.9878\times 0.0319

K_{I} = 5210.45 × 10³  Pa\sqrt{m}  

K_{I} = 5.21 MPa \sqrt{m}

5 0
3 years ago
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