Answer:
The minimum mass flow rate will be "330 kg/s".
Explanation:
Given:
For steam,


For water,


They add energy efficiency as condenser becomes adiabatic, with total mass flow rate of minimal vapor,
⇒ 
On putting the estimated values, we get
⇒ 
⇒ 
⇒ 
Answer:
The heat input from the combustion phase is 2000 watts.
Explanation:
The energy efficiency of the heat engine (
), no unit, is defined by this formula:
(1)
Where:
- Heat input, in watts.
- Power output, in watts.
If we know that
and
, then the heat input from the combustion phase is:




The heat input from the combustion phase is 2000 watts.
Answer: The exit temperature of the gas in deg C is
.
Explanation:
The given data is as follows.
= 1000 J/kg K, R = 500 J/kg K = 0.5 kJ/kg K (as 1 kJ = 1000 J)
= 100 kPa, 

We know that for an ideal gas the mass flow rate will be calculated as follows.

or, m = 
=
= 10 kg/s
Now, according to the steady flow energy equation:




= 5 K
= 5 K + 300 K
= 305 K
= (305 K - 273 K)
= 
Therefore, we can conclude that the exit temperature of the gas in deg C is
.
Answer:
Magnitude of velocity=10.67 m/s
Magnitude of acceleration=24.62 ft/
Explanation:
The solution of the problem is given in the attachments