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MrRissso [65]
3 years ago
15

Anyone who guesses what this means gets brainliest answer!!

Physics
2 answers:
allsm [11]3 years ago
8 0
Guten tag means good day and wie geht es dir means how are you
hram777 [196]3 years ago
3 0

Answer:

I believe this is German for something day how are you????? I was talking about the holocaust again in school and decided to start learning German so if im wrong then.. wowww!

Explanation:

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A man standing in front of a mountain beats a drum at regular intervals. The rate of drumming is generally increased and he find
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A box is at rest on a table. What can you say about the forces acting on the box?
GarryVolchara [31]

the upward force is from the table and the downward is from gravity they are equal in force so the box doesn't fly up or sink down


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Light travels fastest when moving through
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What is the speed of a wave that has a frequency of 125 Hz and a wavelength of 1.25 meters?
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5 0
3 years ago
To push a 26.0 kg crate up a frictionless incline, angled at 25.0° to the horizontal, a worker exerts a force of 209 N parallel
alukav5142 [94]

Answer:

(a) W = +397.1 J

(b) W = -204.6 J

(c) W = 0

(d) W= + 192.5 J

Explanation:

Work (W) is defined as the product of force (F) by the distance (d)the body travels due to this force. :

W= F*d Formula ( 1)

The forces that perform work on an object must be parallel to its displacement.

The forces perpendicular to the displacement of an object do not perform work on it.

The work is positive (W+) if the force has the same direction of movement of the object.  

The work is negative (W-) if the force has the opposite direction of the movement of the object.

Problem development

(a) Work performed by the worker's applied force on the box .

W= 209 N * 1.9 m = +397.1 J

(b) Work performed by the gravitational force on the crate

We calculate the weight component parallel to the displacement of the box:

We define the x-axis in the direction of the inclined plane ,25.0° to the horizontal.

We define the y-axis and in the direction of the plane perpendicular to the inclined plane.

W= m*g=26*9.8= 254.8N : total box weight

Wx= W*sen25.0°= 254.8*sen25.0°= 107.68 N

W = -Wx *d =107.68 N *1.9 m= -204.6 J

(c) Work performed by normal force (N) exerted by the incline on the crate

The force N is perpendicular to the displacement, then:

W=0

(d) Total work done on the crate

W = 397.1 J -204.6 J

W = 192.5 J

4 0
3 years ago
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