Answer:
V₂= 1 L
Explanation:
Given that
Volume occupies V₁= 6 L
Initial pressure = P₁
Initial temperature = T₁
The final pressure =P₂ = 2 P₁
Final volume =V₂
Final temperature = T₁/3
As we know that equation for ideal gas
P V = m R T
P=pressure, V=volume, T=temperature
m=mass ,R=gas constant
Now from mass conservation
![m=\dfrac{P_1V_1}{RT_1}=\dfrac{P_2V_2}{RT_2}](https://tex.z-dn.net/?f=m%3D%5Cdfrac%7BP_1V_1%7D%7BRT_1%7D%3D%5Cdfrac%7BP_2V_2%7D%7BRT_2%7D)
![\dfrac{P_1V_1}{RT_1}=\dfrac{P_2V_2}{RT_2}](https://tex.z-dn.net/?f=%5Cdfrac%7BP_1V_1%7D%7BRT_1%7D%3D%5Cdfrac%7BP_2V_2%7D%7BRT_2%7D)
![\dfrac{P_1\times 6}{RT_1}=3\times \dfrac{2P_1V_2}{RT_1}](https://tex.z-dn.net/?f=%5Cdfrac%7BP_1%5Ctimes%206%7D%7BRT_1%7D%3D3%5Ctimes%20%5Cdfrac%7B2P_1V_2%7D%7BRT_1%7D)
6 = 3 x 2 V₂
V₂= 1 L
So the final volume will be 1 L
The solubility of gases in liquids increases with the increase in pressure.
Answer:
The net magnetic field ta the center of square is
.
Explanation:
Current, I = 12 A , side ,a = 10 cm = 0.1 m
Let the magnetic field due to the one side is B.
The magnetic field is given by
![B = \frac{\mu o}{4\pi}\times \frac{I}{r}\times \left (Sin A +Sin B \right )\\\\B = 10^{-7}\times \frac{12}{0.05}\times \left ( sin 45 + sin 45 \right )\\\\B = 3.4\times 10^{-5} T](https://tex.z-dn.net/?f=B%20%3D%20%5Cfrac%7B%5Cmu%20o%7D%7B4%5Cpi%7D%5Ctimes%20%5Cfrac%7BI%7D%7Br%7D%5Ctimes%20%5Cleft%20%28Sin%20A%20%2BSin%20B%20%20%5Cright%20%29%5C%5C%5C%5CB%20%3D%2010%5E%7B-7%7D%5Ctimes%20%5Cfrac%7B12%7D%7B0.05%7D%5Ctimes%20%5Cleft%20%28%20sin%2045%20%2B%20%20sin%2045%20%20%5Cright%20%29%5C%5C%5C%5CB%20%3D%203.4%5Ctimes%2010%5E%7B-5%7D%20T)
Net magnetic field at the center of the square is
B' = 4 B
![B'= 4\times 3.4\times 10^{-5}\\\\B' = 1.36\times10^{-4} T](https://tex.z-dn.net/?f=B%27%3D%204%5Ctimes%203.4%5Ctimes%2010%5E%7B-5%7D%5C%5C%5C%5CB%27%20%3D%201.36%5Ctimes10%5E%7B-4%7D%20T)
On an extremely warm day, the balloon might pop because gases expand the hotter they get, and due to its temperature it is likely to pop if it is, indeed, nearly, if not completely, filled to its capacity. I hope this helps, have a nice day!
<span>3.78 m
Ignoring resistance, the ball will travel upwards until it's velocity is 0 m/s. So we'll first calculate how many seconds that takes.
7.2 m/s / 9.81 m/s^2 = 0.77945 s
The distance traveled is given by the formula d = 1/2 AT^2, so substitute the known value for A and T, giving
d = 1/2 A T^2
d = 1/2 9.81 m/s^2 (0.77945 s)^2
d = 4.905 m/s^2 0.607542 s^2
d = 2.979995 m
So the volleyball will travel 2.979995 meters straight up from the point upon which it was launched. So we need to add the 0.80 meters initial height.
d = 2.979995 m + 0.8 m = 3.779995 m
Rounding to 2 decimal places gives us 3.78 m</span>