Answer:
option d = 3.125 g
Explanation:
Given data:
Mass of chemical = 100 g
Half life = 8 days
mass left after 40 days = ?
Solution:
First of all we will calculate the total half life's,
half life's = T (elapsed) / T half life
half life's = 40 / 8 = 5
starting mass = 100 g
half life's 1 2 3 4 5
Mass 100/2 50/2 25/2 12.5/2 6.25/2
50 g 25 g 12.5 g 6.25 g 3.125 g
2.50 moles (55.85gramsof Fe/ 1 mole) (6.02 x 10^23 atoms / 1) = 8.41 x 10^25 because there is only one Iron present in the compund.
Answer:
Partial pressure SO₂ → 0.440 atm
Explanation:
We apply the mole fraction concept to solve this:
Moles of gas / Total moles = Partial pressure of the gas / Total pressure
Total moles = 0.3 moles of CO₂ + 0.2706 moles of SO₂ + 0.35 moles H₂O
Total moles = 0.9206 moles
Mole fraction SO₂ = 0.2706 moles / 0.9206 moles → 0.29
Now, we can know the partial pressure:
0.29 = Partial pressure SO₂ / Total pressure
0.29 = Partial pressure SO₂ / 1.5 atm
0.29 . 1.5atm = Partial pressure SO₂ → 0.440 atm
5= chemicals
6= hormones
Don't know the other ones.
