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Fudgin [204]
4 years ago
5

i know this is a lot to do but i will give you the highest amount of points (100, but you get 50 from it.) and i will cash app y

ou $20 just tell me your cash app in the comments. please don't post troll answers. please be legit! this is due at 11:59 today, so in about 5 hours. the questions are in the images below. thank you so much!

Physics
1 answer:
victus00 [196]4 years ago
5 0

Answer:

mel mel 4 ever

Explanation:

You might be interested in
What is the bouncing of light when it changes media
matrenka [14]

When light passes from one medium to another, part of it continues on
into the new medium, while the rest of it bounces away from the boundary,
back into the first medium.

The part of the light that continues on into the new medium is <em>transmitted</em>
light.  Its forward progress at any point in its journey is <em>transmission</em>. 

Its direction usually changes as it crosses the boundary.  The bending is <em>
refraction</em>
.

The part of the light that bounces away from the boundary and heads back
into the first medium is <em>reflected</em> light.  The process of bouncing is <em>reflection</em>.


5 0
3 years ago
Which of the following is not a colligative property? a. osmotic pressure b. lattice energy c. vapor-pressure lowering d. boilin
Gre4nikov [31]

Answer:

b) lattice energy

Explanation:

A solution is said to have colligative property when the property depends on the solute present in the solution.

Colligative property depend upon on the solute particle or the ion concentration not on the identity of solute.

osmotic pressure, vapor pressure lowering , boiling point elevation and freezing point lowering all depend upon solute concentration so they will not have colligative property so, the answer remains option 'b' which is lattice energy.

8 0
3 years ago
8. Express 2.69 x 10^9 in standard form.
taurus [48]

Answer:

242.1

Explanation:

10 x 9 equals 90

2.69 x 90 = 242.1

5 0
3 years ago
A single conducting loop of wire has an area of 7.26E-2 m2 and a resistance of 117 Ω. Perpendicular to the plane of the loop is
cricket20 [7]

Answer:

\frac{dB}{dt} = 591.45 T/s

Explanation:

i = induced current in the loop = 0.367 A

R = Resistance of the loop = 117 Ω

E = Induced voltage

Induced voltage is given as

E = i R

E = (0.367) (117)

E = 42.939 volts

\frac{dB}{dt} = rate of change of magnetic field

A = area of loop = 7.26 x 10⁻² m²

Induced emf is given as

E = A\frac{dB}{dt}

42.939 = (7.26\times 10^{-2})\frac{dB}{dt}

\frac{dB}{dt} = 591.45 T/s

3 0
3 years ago
stion 13 of 20 : Select the best answer for the question. 13. If a certain mass of mercury has a volume of 0.002 m3 at a tempera
Free_Kalibri [48]

Answer : The correct option is, (A) 0.002010812m^3

Solution : Given,

Volume of mercury at temperature 20^oC = 0.002m^3

As we know that the mercury is a liquid substance. So, we have to apply the volume of expansion of the liquid.

Formula used for the volume expansion of liquid :

V_{T}=v_{1}[1+\gamma (T_{2}-T_{1})]

or,

V_{2}=V_{1}[1+\gamma (T_{2}-T_{1})]

where,

V_{T} = volume of liquid at temperature T^oC

V_{1} = volume of liquid at temperature 20^oC

V_{2} = volume of liquid at temperature 50^oC

\gamma = volume expansion coefficient of mercury at 20^oC is 0.00018 per centigrade    (Standard value)

Now put all the given values in the above formula, we get the volume of mercury at 50^oC.

V_{2}=0.002[1+0.00018(50-20)]=0.0020108m^3

Therefore, the volume of mercury at 50^oC is, 0.002010812m^3

7 0
4 years ago
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