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Fudgin [204]
4 years ago
5

i know this is a lot to do but i will give you the highest amount of points (100, but you get 50 from it.) and i will cash app y

ou $20 just tell me your cash app in the comments. please don't post troll answers. please be legit! this is due at 11:59 today, so in about 5 hours. the questions are in the images below. thank you so much!

Physics
1 answer:
victus00 [196]4 years ago
5 0

Answer:

mel mel 4 ever

Explanation:

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Isabela is an astronomer studying stars A and B. Star A is farther away from Isabela and yet when Isabela observes the stars, th
kakasveta [241]

Answer: star A is more luminous

Explanation:

7 0
3 years ago
Calculation using Ohm's Law: If a circuit has a voltage of 500 V and a resistance of 250 ohms, what is the current?
konstantin123 [22]

I = V / R

Current = (voltage) / (resistance)

Current = (500 V) / (250 ohms)

Current = (500/250) Amperes

<em>Current = 2 Amperes</em>

6 0
3 years ago
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A word that means to squeeze a gas in to a smaller place
Leona [35]
I think the best word here would be compress. It is to compress that is defined as to squeeze a gas into a smaller space. Compression is the reduction of volume which cause an increase in pressure of the gas. Hope this answers the question. Have a nice day.

6 0
3 years ago
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Which astronomer supported the belief that earth was at the center fo the universe?
MissTica
B. Ptolemy believed that the earth was the center of the universe
4 0
4 years ago
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Starting from Newton’s law of universal gravitation, show how to find the speed of the moon in its orbit from the earth-moon dis
WARRIOR [948]

Answer: 1010.92 m/s

Explanation:

According to Newton's law of universal gravitation:

F=G\frac{Mm}{r^{2}} (1)

Where:

F is the gravitational force between Earth and Moon

G=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}} is the Gravitational Constant  

M=5.972(10)^{24} kg is the mass of the Earth

m=7.349(10)^{22} kg is the mass of the Moon

r=3.9(10)^{8} m is the distance between the Earth and Moon

Asuming the orbit of the Moon around the Earth is a circular orbit, the Earth exerts a centripetal force on the moon, which is equal to F:

F=m.a_{C} (2)

Where a_{C} is the centripetal acceleration given by:

a_{C}=\frac{V^{2}}{r} (3)  

Being V the orbital velocity of the moon

Making (1)=(2):

m.a_{C}=G\frac{Mm}{r^{2}} (4)

Simplifying:

a_{C}=G\frac{M}{r^{2}} (5)

Making (5)=(3):

\frac{V^{2}}{r}=G\frac{M}{r^{2}} (6)  

Finding V:

V=\sqrt{\frac{GM}{r}} (7)

V=\sqrt{\frac{(6.674(10)^{-11}\frac{m^{3}}{kgs^{2}})(5.972(10)^{24} kg)}{3.9(10)^{8} m}} (8)

Finally:

V=1010.92 m/s

5 0
3 years ago
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