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Hoochie [10]
4 years ago
6

Does anyone understand this stuff?

Physics
2 answers:
Airida [17]4 years ago
7 0
<span>This question can be solved as follows:

A discount offered = (100-18)(100-12)/(100*100)
B discount offered = (100-17)(100-13)/(100*100)</span>
denis23 [38]4 years ago
5 0

Answer:

Manufacturer A: 0.2784 or 27.84%

Manufacturer B: 0.2779 or 27.79%

Therefore, there is not much of a relevant difference but still manufacturer A has a better offer.

Explanation:

calculating the equivalent final discount rate using the formula:

FD= [1- (1-D1(%)) x (1-D2(%))]

D1: first discount to retail price (%)

D2: second discount to the first net price (%)

FD: Final equivalent discount rate (%)

observation: the expression can always be expanded to add more chain discounts using the same principles.

*Manufacturer A 18/12

Chain Discount:  D1= 18 D2= 12

FD= [1- (1- 0.18) x (1-0.12)] ≅ 0.2784

* Manufacturer B 17/13

Chain Discount: D1= 17 D2= 13

FD= [1- (1- 0.17) x (1-0.13)] ≅ 0.2779

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Consider a 24.0 V storage battery that can transfer, over the course of its useful lifetime, a total charge equivalent to 340000
xeze [42]

Answer:

Explanation:

Given that,

Potential difference of battery is

V = 24V

Total charge battery can transferred

q = 340,000C

Work done by the battery?

Work done is given as

W = qV

Where q is charge in Columbs

V is potential difference in Volts

Then, W = qV

W = 340,000×24

W = 8,160,000 J

Work done by the battery over it's useful life time is 8,160,000J

5 0
3 years ago
Two waves are superposed. one wave has an amplitude of 5 cm, and other has an amplitude of 4 cm. What is the resultant amplitude
Vsevolod [243]
If both waves have the same wavelength, then the amplitude of
their sum could be anything between 1 cm and 9 cm, depending
on the phase angle between them.

If the waves have different wavelengths, then the resultant is a beat
with an amplitude of 9 cm.
4 0
3 years ago
A bin is given a push across a horizontal surface. The bin has a mass m, the push gives it an initial speed of 1.60 m/s, and the
emmasim [6.3K]

Answer:

The bin moves 0.87 m before it stops.

Explanation:

If we analyze the situation and apply the law of conservation of energy to this case, we get:

Energy Dissipated through Friction = Change in Kinetic Energy of Bin (Loss)

F d = (0.5)(m)(Vi² - Vf²)

where,

F = Frictional Force = μR    

but, R = Normal Reaction = Weight of Bin = mg

Therefore, F = μmg

Hence, the equation becomes:

μmg d = (0.5)(m)(Vi² - Vf²)

μg d = (0.5)(Vi² - Vf²)

d = (0.5)(Vi² - Vf²)/μg

where,

Vf = Final Velocity = 0 m/s (Since, bin finally stops)

Vi = Initial Velocity = 1.6 m/s

μ = coefficient of kinetic friction = 0.15

g = 9.8 m/s²

d = distance moved by bin before coming to stop = ?

Therefore,

d = (0.5)[(1.6 m/s)² - (0 m/s)²]/(0.15)(9.8 m/s²)

<u>d = 0.87 m</u>

5 0
3 years ago
Which statements about water are true? Choose more than one answer.
insens350 [35]

water is not found in the periodic table.

water has a lot of empty space.

I think that's it I know those to are true.

4 0
3 years ago
A sample of oxygen gas with a volume of 3.0 m3 is at 100 C. The gas is heated so that
vesna_86 [32]

\qquad\qquad\huge\underline{{\sf Answer}}

According to Charles law, if pressure remains constant, volume varies directly with temperature. so we can infer that :

\qquad\sf{\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}}

So, we can use this formula to find out the final temperature of the gas ~

Note : Take temperature in Kelvin ( 100°C = 373 K )

\qquad \sf  \dashrightarrow \:  \dfrac{3}{373}  =  \dfrac{6}{x}

\qquad \sf  \dashrightarrow \: x =  \dfrac{6}{3} \times 373

\qquad \sf  \dashrightarrow \: x = 2 \times 373

\qquad \sf  \dashrightarrow \: x =74 6 \: K

Now, convert it to Celsius ~

i.e 746 - 273 = 473° C

So, the final temperature of the gas will be equal to 473° C

6 0
2 years ago
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