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3 years ago

Does anyone understand this stuff?

2 answers:

7 0

<span>This question can be solved as follows:

A discount offered = (100-18)(100-12)/(100*100)
B discount offered = (100-17)(100-13)/(100*100)</span>

denis23 [38]3 years ago

5 0

Answer:

Manufacturer A: 0.2784 or 27.84%

Manufacturer B: 0.2779 or 27.79%

Therefore, there is not much of a relevant difference but still manufacturer A has a better offer.

Explanation:

calculating the equivalent final discount rate using the formula:

FD= [1- (1-D1(%)) x (1-D2(%))]

D1: first discount to retail price (%)

D2: second discount to the first net price (%)

FD: Final equivalent discount rate (%)

observation: the expression can always be expanded to add more chain discounts using the same principles.

*Manufacturer A 18/12

Chain Discount: D1= 18 D2= 12

FD= [1- (1- 0.18) x (1-0.12)] ≅ 0.2784

* Manufacturer B 17/13

Chain Discount: D1= 17 D2= 13

FD= [1- (1- 0.17) x (1-0.13)] ≅ 0.2779

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A group of students is measuring the change in momentum of an object. Which set of lab equipment would be most in measuring the

a_sh-v [17]

Answer:

The momentum of an object is defined as the mass of the object times the velocity of the object, as P = m*v.

So the equipment needed would be:

Something to measure the mass of the object, like a balance.

Something to measure the speed of the object, like a doppler radar, or a simpler thing may be a cronometer, with that you can measure the amount of time that the object needs to travel a given distance, and with that you can obtain the speed of the object.

Now you can notice that speed is different than velocity, this is true, velocity is a vector, so this has a direction, then you need something to fix the direction in which the object moves, in this way you can determine the velocity.

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3 years ago

Monochromatic light from a distant source is incident on a slit 0.750 mm wide. On a screen 2.00 m away, the distance from the ce

jasenka [17]

Answer:

$\lambda= 506.25 nm$

Explanation:

Diffraction is observed when a wave is distorted by an obstacle whose dimensions are comparable to the wavelength. The simplest case corresponds to the Fraunhofer diffraction, in which the obstacle is a long, narrow slit, so we can ignore the effects of extremes.

This is a simple case, in which we can use the Fraunhofer single slit diffraction equation:

$y=\frac{m \lambda D}{a}$

Where:

$y=Displacement\hspace{3}from\hspace{3} the\hspace{3} centerline \hspace{3}for \hspace{3}minimum\hspace{3} intensity =1.35mm\\\lambda=Light\hspace{3} wavelength \\D=Distance\hspace{3}between\hspace{3}the\hspace{3}screen\hspace{3}and\hspace{3}the\hspace{3}slit=2m\\a=width\hspace{3}of\hspace{3}the\hspace{3}slit=0.750mm\\m=Order\hspace{3}number=1$

Solving for λ:

$\lambda=\frac{y*a}{mD}$

Replacing the data provided by the problem:

$\lambda=\frac{(1.35\times 10^{-3})*(0.750\times 10^{-3})}{1*2} =5.0625\times 10^{-7}m =506.25nm$

7 0

2 years ago

BRAINLIESTTT!! HELP ME!!!

likoan [24]

The efficiency of the scissor is 200%.

<u>Explanation:</u>

Efficiency is defined as the ratio of output of any instrument or device or machine to the input supplied to it. So the greater the output the greater will be the efficiency of the device.

As here the work done by us on the system is said to be 10 J so this will be equal to the input work done on the system. And the work done by the system i.e., the scissor is 20 J, so this will be the output work.

So, the efficiency is the ratio of output to input as shown below.

Efficiency = $(\frac {20} {10} ) \times 100$ = 200

So, the efficiency of the scissor is 200%.

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3 years ago

In the equation for the gravitational force between two objects, which quantity must be squared?

Alex787 [66]

Answer:

The distance between the two objects must be squared.

Explanation:

Gravitational force always act between two objects that have mass. The gravitational force is a weak force and attractive in nature.

The force of pull depends on the masses of the two objects and the distance between them.

The formula to calculate gravitational force between two objects having masses 'm' and 'M' and separated by a distance 'd' is given as:

$F_g=\frac{GmM}{d^2}$

Where, 'G' is called the universal gravitational constant and its value is equal to $6.674\times10^{-11}\ m^3 kg^{-1} s^{-2}$ .

Now, from the above formula, it is clear that, the force of gravitation is inversely proportional to the square of the distance between the two objects.

Thus, the quantity that must be squared in the equation of gravitational force between two objects is the distance 'd'.

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3 years ago

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weqwewe [10]

Answer:

A.always changing

Explanation:

7 0

2 years ago

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