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3 years ago

Describe the advantages and disadvantages of keeping the road clear of ice

1 answer:

4 0

A advantage is less car accidents and a disadvantage is, in order to keep the roads clear of ice is a chemical. Like salt. Which is bad for the animals.

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A thin beam of light of wavelength 50 μm (in the infrared portion of the em spectrum) goes through

Brut [27]

Solution :

Given :

Wavelength of the thin beam of light, λ = 50 μm

Distance of the screen from the slit, D = 3.00 m

Width of the fringe, Δy = ±8.24 mm

Therefore, width of the slit is given by :

$d=\frac{n \lambda D}{\Delta y}$

$=\frac{2 \times 50 \times 10^{-9} \times 3}{2 \times 8.24 \times 10^{-3}}$

= 0.000018203 m

= 0.0182 mm

= 0.018 mm

The intensity of light is given by :

$I=I_0\left(\frac{\sin \beta /2}{\beta/ 2}\right)^2$ , where $\beta=\frac{2 \pi D \sin \theta}{\lambda}$

$I=I_0\left(\frac{\sin \frac{\pi d \sin \theta}{\lambda}}{\frac{\pi d \sin \theta}{\lambda}}\right)^2$

$I=I_0\left(\frac{\sin \frac{\pi d y}{D\lambda}}{\frac{\pi d y}{D\lambda}}\right)^2$

Now, $\frac{dy}{D \lambda} = \frac{8.24 \times 10^{-3}\times 0.018 \times 10^{-3}}{4 \times 50\times 10^{-9}\times 4}$

= 0.1854

≈ 0.18

$I=I_0\left(\frac{\sin 0.56}{0.56}\right)^2$

$=I_0 \times 0.81$

= 2 x0.81

$= 1.62 \ W/m^2$

6 0

3 years ago

In a control system, an accelerometer consists of a 4.70-g object sliding on a calibrated horizontal rail. A low-mass spring att

irga5000 [103]

Answer:

7.37 N/m

Explanation:

Given:

Mass of the object = 4.70 g = 0.0047 kg

acceleration = 0.800 g = 0.800 × 9.81 = 7.848 m/s²

Displacement = 0.500 cm = 0.005 m

Now,

Force by the object = Mass × Acceleration

= 0.0047 × 7.848

= 0.0368856 N

and,

Force by the spring = kx

where, x is the displacement

k is the spring constant

thus,

0.0368856 = k × 0.005

k = 7.37 N/m

6 0

3 years ago

Antrenmanlarla matematik 17.gün cevaplari acil

Ray Of Light [21]

Answer:

ne diyorsun anlamadım cevap anhtarımı

7 0

3 years ago

What would happen if you added energy to solid bar of gold ?

kolezko [41]

Thats imposiblie u cant ad energy to gold bar

8 0

3 years ago

A sound wave produced by a chime 515 m away is heard 1.50 s later. What is the speed of the sound in the air?

aliina [53]

Answer:

the speed of the sound in the air is 343.3 m/s

Explanation:

The computation of the speed of the sound in the air is shown below:

As we know that

Speed = Distance ÷ time

So, here speed be 515 m

And, the time is 1.50 seconds

So, the speed of the sound is

= 515 m ÷ 1.50 seconds

= 343.3 m/s

hence, the speed of the sound in the air is 343.3 m/s

6 0

3 years ago