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Mekhanik [1.2K]
3 years ago
9

A box is being pulled to the right. What is the direction of the gravitational force? up down right left

Physics
2 answers:
BigorU [14]3 years ago
8 0
Down because gravitational force always pullls down
astraxan [27]3 years ago
3 0
The direction of the gravitational farce is down and always is. Gravity keeps us and everything down.

hope this helps :)
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A worker on the roof of a house drops his 0.58 kg hammer, which slides down the roof at constant speed of 6.69 m/s. The roof mak
shusha [124]

Answer:

17.3 m

Explanation:

Given that,

Mass of a hammer is 0.58 kg

Velocity with which the hammer slides is 6.69 m/s at constant speed.

The roof makes an angle of 18 ◦ with the horizontal, and its lowest point is 18.2 m from the ground. We need to find the horizontal distance traveled by the hammer between the time is leaves the roof of the house and the time it hits the ground. Firstly, we will find the time taken by the hammer when it reaches ground in vertical direction.

y=y_0+v_ot +\dfrac{1}{2}gt^2

Putting all the values,

0=18.2+6.69t-\dfrac{1}{2}\times 9.8t^2\\\\-4.9t^2+6.69t+18.2=0\\\\t=\dfrac{-6.69+\sqrt{6.69^{2}-4\cdot-4.9\cdot18.2}}{2\cdot-4.9}, \dfrac{-6.69-\sqrt{6.69^{2}-4\cdot-4.9\cdot18.2}}{2\cdot-4.9}\\\\t=-1.36\ s\ \text{and}\ t=2.72\ s

Neglecting negative value,

To find horizontal distance, multiply 2.72 s with the horizontal component of velocity.

d=2.72\times 6.69\times \cos(18)\\\\d=17.3\ m

3 0
3 years ago
Two tugboats pull a disabled supertanker. Each tug exerts a constant force of 2.20×106 N , one at an angle 19.0 ∘ west of north,
valina [46]

Answer:

=2.99\times10^9J

Explanation:

According to the question

net force F = 2.20×10^6 N

displacement S = 0.72\times10^3m

from figure , the horizontal forces are same in magnitude and opposite direction.

so , neglect these two forces.

we can take only vertical components of the force.

total force F' = F cos 19° + F cos 19°

= 2×F×cos 19°   ................. (1

therefore , total work is

W = F'S

= (2F cos19)×S

= (2)(2.20\times10^6 N)cos19° (0.720\times10^3 m)

=2.99\times10^9J

6 0
3 years ago
PLZ HELP Lab: Circuit Design
Masteriza [31]

Answer:

3

Explanation:

6 0
2 years ago
Tell me pls<br>question: one way to protect property from damage. (hurricane) (hurricane)​
postnew [5]

Answer:

hide on a place where there is no windows take a radio

Explanation:

5 0
3 years ago
Read 2 more answers
If it takes an amount of work W to move two q point charges from infinity to a distance d apart from each other, then how much w
aleksklad [387]

Answer:3W

If it takes an amount of work W to move two q point charges from infinity to a distance d apart from each other, then how much work should it take to move three q point charges from infinity to a distance d apart from each other?

A) 2W

B) 3W

C) 4W

D) 6W

Explanation: calculating work done,W, in moving two positive q point charges from infinity to a valued distance d from each other  is

W = k(+q)(+q)/ d

k is couloumb's constant

work done in moving 3 equal positive charges from infinity to a finite distance is given by

W₂=W₄=W₆=k(+q)(+q)/ d

Total work done, W' =k(+q)(+q)/ d + k(+q)(+q)/ d + k(+q)(+q)/ d

= W + W + W = 3W

7 0
3 years ago
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