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3 years ago

A box is being pulled to the right. What is the direction of the gravitational force? up down right left

Physics

2 answers:

BigorU [14]3 years ago

8 0

Down because gravitational force always pullls down

astraxan [27]3 years ago

3 0

The direction of the gravitational farce is down and always is. Gravity keeps us and everything down.

hope this helps :)

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What are three physical properties of a bowling ball

Sidana [21]

1) round

2)colorful

3)big

3 0

4 years ago

If a horse does 4000 J of work over 20 m, how much force does the horse use?

Eduardwww [97]

If you take a look at the definition of work, you will get this formula:

$W=Fd \\ F= \frac{4000}{20} \\ \boxed {F=200~N}$

8 0

3 years ago

After each charging, a battery is able to hold only 99% of the charge from the previous charging. The battery was used for 5 hou

Aloiza [94]

Answer:

500 hours

Explanation:

The sum of total hours over its lifetime will be given by

$T=\frac {T_o}{1-r}$

Where T is total time, r is rate in decimal and To is the original charge hours. Substituting the original charge hours with 5 hours and rate as 0.99 then the time will be

$T=\frac {5\ hours}{1-0.88}=500\ hours$

Therefore, the time is equivalent to 500 hours

7 0

3 years ago

A single loop of wire with an area of 0.0920 m2 is in a uniform magnetic field that has an initial value of 3.80 T, is perpendic

jekas [21]

Answer:

Induced emf in the loop is 0.02208 volt.

Induced current in the loop is 0.0368 A.

Explanation:

Given that,

Area of the single loop, $A=0.092\ m^2$

The initial value of uniform magnetic field, B = 3.8 T

The magnetic field is decreasing at a constant rate, $\dfrac{dB}{dt}=0.24\ T/s$

(a) The induced emf in the loop is given by the rate of change of magnetic flux.

$\epsilon=\dfrac{-d\phi}{dt}\\\\\epsilon=A\times \dfrac{dB}{dt}\\\\\epsilon=0.092\times 0.24\\\\\epsilon=0.02208\ V$

(b) Resistance of the loop is 0.6 ohms. Let I is the current induced in the loop. Using Ohm's law :

$\epsilon=IR\\\\I=\dfrac{\epsilon}{R}\\\\I=\dfrac{0.02208}{0.6}\\\\I=0.0368\ A$

Hence, this is the required solution.

5 0

3 years ago

A charge Q is transferred from an initially uncharged plastic ball to an identical ball 24 cm away.The force of attraction is th

xxMikexx [17]

Answer:

The number of electrons transferred from one ball to the other is 2.06 x 10¹² electrons

Explanation:

Given;

magnitude of the attractive force, F = 17 mN = 0.017 N

distance between the two objects, r = 24 cm = 0.24 m

The attractive force is given by Coulomb's law;

$F = \frac{1}{4\pi \epsilon _0} \times \frac{Q^2}{r^2} = \frac{kQ^2}{r^2} \\\\Q^2 = \frac{Fr^2}{k} \\\\Q = \sqrt{ \frac{Fr^2}{k}} \\\\Q = \sqrt{ \frac{(0.017)(0.24)^2}{9\times 10^9}} \\\\Q = 3.298 \times 10^{-7} \ C$

The charge of 1 electron = 1.602 x 10⁻¹⁹ C

n(1.602 x 10⁻¹⁹ C) = 3.298 x 10⁻⁷

$n = \frac{3.298 \times 10^{-7}}{1.602 \times 10^{-19}} = 2.06 \times 10^{12} \ electrons$

Therefore, the number of electrons transferred from one ball to the other is 2.06 x 10¹² electrons

4 0

3 years ago