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Natali [406]
3 years ago
6

What are beats? A. periodic fluctuations in the velocity of sound waves B. periodic fluctuations in the wavelength of sound wave

s C. periodic fluctuations in the intensity of sound waves D. periodic fluctuations in the frequency of sound waves
Physics
2 answers:
Ne4ueva [31]3 years ago
6 0

Answer:

D. periodic fluctuations in the frequency of sound waves

Explanation:

Beat is referred to the phenomena that occurs when to sound waves interfer with each other and they have different frequencies.

This difference is what creates a beating, wich in sound waves manifest as high and low sounds, this as a result of the oscilating frequency .

777dan777 [17]3 years ago
3 0

The answer is

C. periodic fluctuations in the intensity if sound waves.

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An eagle carries a fish up 50 m into the sky using 90 N of force. How much work did the eagle do on the fish? (Work: W = Fd)
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<span>Work: W = Fd. 50(distance) multiplied by 90(force) would equal 4500 J or, answer D</span>
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3 years ago
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The platform height for Olympic divers is 10 m. A 60 kg diver steps off the platform to begin his dive.
azamat

Answer:

a) Ep = 5886[J]; b) v = 14[m/s]; c)   W = 5886[J]; d) F = 1763.4[N]

Explanation:

a)

The potential energy can be found using the following expression, we will take the ground level as the reference point where the potential energy is equal to zero.

E_{p} =m*g*h\\where:\\m = mass = 60[kg]\\g = gravity = 9.81[m/s^2]\\h = elevation = 10 [m]\\E_{p}=60*9.81*10\\E_{p}=5886[J]

b)

Since energy is conserved, that is, potential energy is transformed into kinetic energy, the moment the harpsichord touches water, all potential energy is transformed into kinetic energy.

E_{p} = E_{k} \\5886 =0.5*m*v^{2} \\v = \sqrt{\frac{5886}{0.5*60} }\\v = 14[m/s]

c)

The work is equal to

W = 5886 [J]

d)

We need to use the following equation and find the deceleration of the diver at the moment when he stops his velocity is zero.

v_{f} ^{2}= v_{o} ^{2}-2*a*d\\where:\\d = 2.5[m]\\v_{f}=0\\v_{o} =14[m/s]\\Therefore\\a = \frac{14^{2} }{2*2.5} \\a = 39.2[m/s^2]

By performing a sum of forces equal to the product of mass by acceleration (newton's second law), we can find the force that acts to reduce the speed of the diver to zero.

m*g - F = m*a

F = m*a - m*g

F = (60*39.2) - (60*9.81)

F = 1763.4 [N]

3 0
3 years ago
What is the beat frequency of two keys on a phone, one with a frequency of 210 Hz and the other one with a frequency of 280 Hz?
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The best frequency should be 70 Hz you simply find the difference between 280 Hz and 210 Hz
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2 years ago
A wire connected to red and green terminals on a grey box, which contains a white box with a needle pointing up. The wire passes
harkovskaia [24]

Answer:

A Magnet

Explanation:

Edge 2021

3 0
3 years ago
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The Indianapolis speedway consists of a 2.5 mile track having four turns, each 0.25 mile long and banked at 9 12'
blsea [12.9K]

Answer: Your question is missing below is the question

Question : What is the no-friction needed speed (in m/s ) for these turns?

answer:

20.1 m/s

Explanation:

2.5 mile track

number of turns = 4

length of each turn = 0.25 mile

banked at 9 12'

<u>Determine the no-friction needed speed </u>

First step : calculate the value of R

2πR / 4 =  πR / 2

note : πR / 2 = 0.25 mile

∴ R = ( 0.25 * 2 ) / π

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Finally no-friction needed speed

tan θ = v^2 / gR

∴ v^2 = gR * tan θ

 v = √9.81 * 256 * tan(9.2°)  = 20.1 m/s

8 0
3 years ago
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