Answer:
B and C
Explanation:
The correct answer is Condensation and Deposition
Answer:
[C₆H₅COO⁻][H₃O⁺]/[C₆H₅COOH] = Ka
Explanation:
The reaction of dissociation of the benzoic acid in water is given by the following equation:
C₆H₅-COOH + H₂O ⇄ C₆H₅-COO⁻ + H₃O⁺ (1)
The dissociation constant of an acid is the measure of the strength of an acid:
HA ⇄ A⁻ + H⁺ (2)
(3)
<em>Where the dissociation constant of the acid (Ka) is equal to the ratio of the concentration of the dissociated forms of the acid, [A⁻][H⁺], and the concentration of the acid, [HA]. </em>
So, starting from the equations (2) and (3), the constant equation for the dissociation reaction of benzoic acid in water, of the equation (1), is:
![K_{a} = \frac{[C_{6}H_{5}COO^{-}][H_{3}O^{+}]}{[C_{6}H_{5}COOH]}](https://tex.z-dn.net/?f=%20K_%7Ba%7D%20%3D%20%5Cfrac%7B%5BC_%7B6%7DH_%7B5%7DCOO%5E%7B-%7D%5D%5BH_%7B3%7DO%5E%7B%2B%7D%5D%7D%7B%5BC_%7B6%7DH_%7B5%7DCOOH%5D%7D%20)
I hope it helps you!
When traveling through a smoke-filled area, a person must be able to have distance of at least 4 feet in order to safely reach a fire exit. That is option C.
<h3>What is a smoke-filled area?</h3>
Smoke-filled area is an enclosed area that is filled with smoke gas that is usually made up of carbon monoxide.
The smoke-filled area is usually caused by
- Burning of plastics or chemical products
When there is smoke-filled area die to fire out break, there are some guidelines to follow to safely reach the fire exit early enough.
The importance of these guidelines include the following:
- enable rescuers to navigate a scene more quickly,
- identify risks and hazards,
- determine the safest way in and out of a building, and
- map out evacuation routes.
The affected individual should get down and crawl while taking short breath through the nose because cleaner air is nearest to the floor.
Learn more about distance here:
brainly.com/question/7243416
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Answer:
2000 mL
Explanation:
Given data:
Number of moles KMnO₄ = 6 mol
Molarity of solution = 3M
Volume of solution in mL = ?
Solution:
Formula:
Molarity = number of moles of solute / volume of solution in L
3 M = 6 mol / volume of solution in L
volume of solution in L = 6 mol/ 3 M
volume of solution in L = 2 L
Now we convert the L into mL:
1 L = 1000 mL
2 L × 1000 mL / 1 L
2000 mL