Given:
v(final velocity)= 7.5 m/s
t(time taken to pedal along)=4.5 s
Displacement (s)=19 m
Now we know that
s=ut+1/2(at^2)
Where s is the displacement measured in m
u is the initial velocity measured in m/sec
a is the acceleration measured in m/s^2.
t is the time taken to cover this distance.
Substituting the given values in the above formula we get
19= 4.5u+1/2(a x 4.5 x 4.5)
20.25 a + 9 u = 38
Now we also know that
v= u + at
Substituting the given values in the above formula we get
7.5= u + 4.5a
Solving for u and a from the above equations we get
u = 0.944m/s
a= 1.45 m/s^2
Thus the initial velocity is 0.944 m/s
Answer:
Then its acceleration is zero.
Explanation:
Velocity → Uniform → Constant
→ Change in Velocity = 0
A= = (v=m)
a=0
Answer:
The magnitude of charge on the particle is .
Explanation:
Given that,
The magnitude of electric field, E = 215 N/C
The electrical potential energy of the charge decreases by, as it moves.
We need to find the magnitude of the charge on the moving particle. The change in electric potential energy is given by :
.........(1)
The electric potential in terms of electric field is given by :
Equation (1) becomes :
So, the magnitude of charge on the particle is .
Answer:
The bulk modulus of the liquid is 1.229 x 10¹⁰ Pa
Explanation:
Given;
density of liquid, ρ = 1400 kg/m³
frequency of the wave, f = 390 Hz
wavelength, λ = 7.60 m
The speed of the sound is given by;
v = fλ
v = 390 x 7.6
v = 2964 m/s
The bulk modulus of the liquid is given by;
where;
B is bulk modulus
B = (1400)(2964)²
B = 1.229 x 10¹⁰ N/m²
B = 1.229 x 10¹⁰ Pa
Therefore, the bulk modulus of the liquid is 1.229 x 10¹⁰ Pa
Answer:
yes you are totally right