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In-s [12.5K]
4 years ago
13

Two long straight wires enter a room through a window. One carries a current of 2.9A into the room, while the other carries a cu

rrent of 4.4 out of the room. Calculate the magnitude (in T.m) of the path integral of B.ds around the window frame.
Physics
1 answer:
Degger [83]4 years ago
4 0

Answer and Explanation:

curents i = 2.9 A

           i ' = 4.4 A

the magnitude (in T.m) of the path integral of B.dl around the window frame = μo * current enclosed

          = μo* ( i '- i )

Since from Ampere's law

where μ o = permeability of free space = 4π * 10 ^-7 H / m

plug the values we get the magnitude (in T.m) of the path integral of B.dl = ( 4π*10^-7 ) (2.9+4.4)

                                 = 1.884 * 10^-6 Tm

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Lila is a track and field athlete. She must complete four laps around a circular track. The track itself is a 400 meter track an
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Answer: 4.45m/s

Explanation:

I assume we're solving for her speed.

400m x 4 laps = 1600m

1600m / 6 minutes = 266.67m/min

(266.67m/min) x (1 minute/60 seconds) = 4.45m/s

266.67/60 = 4.45m/s

6 0
4 years ago
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nikdorinn [45]

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A building is being knocked down with a wrecking ball, which is a big metal sphere that swings on a 15-m-long cable. You are (un
Charra [1.4K]

Answer:

1.9 s

Explanation:

We are given that

Length of cable=l=15 m

We have to find the time you have to move out of the way.

We know that

Time period,T=2\pi\sqrt{\frac{l}{g}}

Where g=9.8m/s^2

By using the formula

T=2\pi\sqrt{\frac{15}{9.8}}

T=2\times 3.14\times \sqrt{\frac{15}{9.8}}=7.77 s

Time you have to move out

t=\frac{T}{4}=\frac{7.77}{4}=1.9 s

Hence,time you have to move out of the way=7.77 s

6 0
4 years ago
Suppose you walk 11 m in a direction exactly 24° south of west then you walk 21 m in a direction exactly 39° west of north. 1) H
DENIUS [597]

Answer:

(1) 42.94 m

(2) 16.02^\circ

Explanation:

Let us first draw a figure, for the given question as below:

In the figure, we assume that the person starts walking from point A to travel 11 m exactly 24^\circ south of west to point B and from there, it walks 21 m exactly 39^\circ west of north to reach point C.

Let us first write the two displacements in the vector form:

\vec{AB} = (-11\cos 24^\circ\ \hat{i}-11\sin 24^\circ\ \hat{j})\ m =(-10.05\ \hat{i}-4.47\ \hat{j})\ m\\\vec{BC} = (-21\sin 39^\circ\ \hat{i}+21\cos 39^\circ\ \hat{j})\ m =(-31.22\ \hat{i}+16.32\ \hat{j})\ m

Now, the vector sum of both these vectors will give us displacement vector from point A to point C.

\vec{AC}=\vec{AB}+\vec{BC}\\\Rightarrow \vec{AC}=(-10.05\ \hat{i}-4.47\ \hat{j})\ m+(-31.22\ \hat{i}+16.32\ \hat{j})\ m\\\Rightarrow \vec{AC}=(-41.25\ \hat{i}+11.85\ \hat{j})\ m

Part (1):

the magnitude of the shortest displacement from the starting point A to point the final position C is given by:

AC=\sqrt{(-41.25)^2+(11.85)^2}\ m= 42.94\ m

Part (2):

As the vector AC is coordinates lie in the third quadrant of the cartesian vector plane whose angle with the west will be positive in the north direction.

The angle of the shortest line connecting the starting point and the final position measured north of west is given by:

\theta = \tan^{-1}(\dfrac{11.85}{41.27})\\\Rightarrow \theta = 16.02^\circ

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3 years ago
Hat is the processes called when matter, that is a liquid, transforms into a gas?
nirvana33 [79]

Answer:

vaporization ,( Evaporation)

8 0
3 years ago
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