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andrey2020 [161]
3 years ago
15

When water has a temperature greater than 100c?

Physics
1 answer:
Ganezh [65]3 years ago
6 0
When water has a temperature greater than 100c, it's boiling
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What constant acceleration is required to increase the speed of a car from 27 mi/h to 53 mi/h in 3s?
mario62 [17]

Answer:

8.87 m/s^2  

Explanation:

Acceleration is change in velocity over a change in time

27 to 53 = 26 m/s   change in velocity

26 m/s / 3 s = 8.87 m /s^2

7 0
1 year ago
The route followed by a hiker consists of three displacement vectors A with arrow, B with arrow, and C with arrow. Vector A with
Zarrin [17]

Answer:

B= 5,655 m  C= 5,890 m.

Explanation:

We are told that the hiker ended up back where she started, so the total displacement was 0.

As displacement is a vector, if the magnitude is 0, this means that their components, along any axis must be 0 too.

If we choose the W-E direction as our x axis (with origin in the start and end point of the travel), being the E direction the positive, and we do the same with the N-S direction (we make it our y axis, with N as positive), we can write the following:

Δx = Δy=0

Next, we sum all the components of A, B and C along x axis, based on the question premises, as follows:

Δx = 1,230 m* cos 36º + B*sin 41º - C*cos 37º =0 (1)

Δy = 1,230 m*sin 36º -B*cos 41º + C* sin 37º = 0

We have a system of 2 linear equations with 2 unknowns (B and C) which can be solved by any suitable method: substitution, sum and substraction, determinants, etc).

Using determinants, we find first the determinant of the unknowns, as follows:

Δ = sin 41º*sin 37º - (-(cos 37º)*(-cos 41º) = -0.208

Now we find the numerator in order to get the value of B, replacing the B column by the independent terms'column:

ΔB = -1230*cos 36º*sin 37º - (-1230*sin 36º*(-cos 37º) = -1,177

⇒ B = ΔB / Δ = -1,177/-0.208 = 5,655 m

Repeating the same process, we get the value for ΔC, as follows:

ΔC = -1230*sin 36º*sin 41º - (-1230*cos 36º*(-cos 41º)) = -1,225

⇒ C = ΔC / Δ = -1,225/-0.208 = 5,890 m

 

3 0
3 years ago
Una onda cuya frecuencia es igual a 550 Hz, se propaga en el aire. ¿ cual es su longitud de onda y su periodo?
oee [108]

Answer:

The wavelength of the wave is 5.45\times 10^5\ m and time period is 0.0018 s.

Explanation:

The given question is, "A wave whose frequency is equal to 550 Hz, propagates in the air. What is its wavelength and its period?"

Given that,

The frequency of a wave, f = 550 Hz

The time period of a wave,

T=\dfrac{1}{f}\\\\T=\dfrac{1}{550}\\\\T=0.0018\ s

Wavelength,

\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{550}\\\\\lambda=5.45\times 10^5\ m

So, wavelength of the wave is 5.45\times 10^5\ m and time period is 0.0018 s.

8 0
2 years ago
a mercury in glass thermometer reads -20° at the ice point and 100°at the steam point. calculate the Celsius temperature corresp
Anestetic [448]

Answer:

120 deg Unknown = 100 deg Celsius since we know that the ice point is at

0 deg Celsius and the steam point is 100 deg Celsius

So you have 1.2 deg U / 1 deg C

70 deg U / (1.2 deg U / 1 deg c) = 58.3 deg C    (temperature in deg Celsius)

Or 58.3deg C * 1.2 deg U / 1 deg C = 70 deg U

4 0
2 years ago
URGENT ANSWER ASAP PLEASE
irakobra [83]

Answer:

learning and memory are very closely related concept . Learning is the acquisition of silk or knowledge, while memory is the expression of what you've acquired.Another difference is the speed with which the two things happen if you acquire the new skill or knowledge slowly and laboriously, that's learning

5 0
3 years ago
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