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4 years ago

Use 4 to 5 complete sentences, explain the concepts of beats and how beats are produces. Please provide at least 2 examples

2 answers:

6 0

Beating in waves is the result of "superposing" - sort of adding together - two waves of different but similar frequencies - eg 50 Hz and 51Hz. The waves go in and out of phase as a sort of continuous or running interference pattern. In the case of sound, you'd hear it as a continuous change in the sound intensity loud in phase, soft out of phase.

allsm [11]4 years ago

6 0

Answer:

Explanation:

The beats are produced, when two sound waves of nearly same frequency and same amplitudes superimposed on each other if they are travelling in same directions.

When the intensity of sound wave is maximum, it is said to be that one bat is produced.

The beat period is defined as the time interval between the two consecutive beats.

The number of beats produces per second is equal to the difference between the frequencies of two sound waves.

Let there are sound waves having frequency 252 Hz and 256 Hz are superimpose on each other they both have nearly same amplitude and moving in same direction.

The beat frequency is 4 beat per second which is equal to the difference between the frequencies of two sound waves.

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A plane has a mass of 360,000 kg takes-off at a speed of 300 km/hr. i) What should be the minimum acceleration to take off if th

melomori [17]

Answer:

i) the minimum acceleration to take off is 22500 km/h²

ii) the required time needed by the plane from starting to takeoff is 0.0133 hrs

iii) required force that the engine must exert to attain acceleration is 625 kN

Explanation:

Given the data in the question;

mass of plane m = 360,000 kg

take of speed v = 300 km/hr = 83.33 m/s

What should be the minimum acceleration to take off if the length of the runway is 2.00 km

from Newton's equation of motion;

v² = u² + 2as

we know that a plane starts from rest, so; u = 0

given that distance S = 2 km

we substitute

(300)² = 0² + ( 2 × a × 2 )

90000 = 4 × a

a = 90000 / 4

a = 22500 km/h²

Therefore, the minimum acceleration to take off is 22500 km/h²

ii) At this acceleration, how much time would the plane need from starting to takeoff.

from Newton's equation of motion;

v = u + at

we substitute

300 = 0 + 22500 × t

t = 300 / 22500

t = 0.0133 hrs

Therefore, the required time needed by the plane from starting to takeoff is 0.0133 hrs

iii) What force must the engines exert to attain this acceleration

we know that;

F = ma

acceleration a = 22500 km/hr² = 1.736 m/s²

so we substitute

F = 360,000 kg × 1.736 m/s²

F = 624960 N

F = 625 kN

Therefore, required force that the engine must exert to attain acceleration is 625 kN

5 0

3 years ago

What mass of silver will occupy a volume of 87.75 mL? The density of silver is 10.49 g/mL.

Anastaziya [24]

Answer:

The mass of silver that will occupy a volume of 87.75 mL is 920.5 grams.

Explanation:

Density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space. In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance. Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

$density=\frac{mass}{volume}$

So the density of silver is 10.49 g / mL indicates that 10.49 g occupies a volume of 1 mL. Then a rule of three can be applied in the following way: if in 1 mL a mass of 10.49 g is occupied, in 87.75 mL how much mass will it occupy?

$mass=\frac{87.75 mL*10.49 g}{1 mL}$

mass= 920.5 g

The mass of silver that will occupy a volume of 87.75 mL is 920.5 grams.

5 0

3 years ago

An airplane accelerates from a speed of 88m/s to a speed of 132 m/s during a 15 second time interval. How far did the airplane t

Gelneren [198K]

Answer:

$1650\:\mathrm{m}$

Explanation:

We can use the following kinematics equations to solve this problem:

$v_f=v_i+at,\\{v_f}^2={v_i}^2+2a\Delta x$ .

Using the first one to solve for acceleration:

$132=88+a(15),\\15a=44,\\a=\frac{44}{15}=2.9\bar{3}\:\mathrm{m/s^2}$ .

Now we can use the second equation to solve for the distance travelled by the airplane:

$132^2=88^2+2\cdot2.9\bar{3}\cdot \Delta x,\\\Delta x= \frac{9680}{2\cdot2.9\bar{3}},\\\Delta x =\fbox{$ 1650\:\mathrm{m}$}$ (three significant figures).

6 0

3 years ago

Two children are pulling and pushing a 30.0 kg sled. The child pulling the sled is exerting a force of 12.0 N at a 45o angle. Th

irinina [24]

I'm not quite sure what happens to Fay so I didn't finish but hope it helps

5 0

3 years ago

Read 2 more answers

The table below shows the distance d(t) in feet that an object travels in t seconds:

vazorg [7]

The rate of change of d(t) at t = 2 and t = 6 is the ratio between the change of distance (difference between the distances) to the time elapsed. That is,
r = (576 - 64) / (6 - 2) = 128 ft /s
The rate of change is equal to 128 ft/s and this represents the average speed at this time interval.

8 0

4 years ago

Read 2 more answers