The answer can be explained when you burn something cleanly (with a very hot item) or not. With a candle lots of Carbon dioxide is producted but when using a bunson burner hardly any CO2 is produced.
Answer: 7.07 grams
Explanation:
To calculate the moles :


According to stoichiometry :
1 mole of
require 1 mole of 
Thus 0.052 moles of
will require=
of 
Thus
is the limiting reagent as it limits the formation of product and
is the excess reagent.
As 1 mole of
give = 1 mole of 
Thus 0.052 moles of
give =
of 
Mass of 
Thus 7.07 g of
will be produced from the given masses of both reactants.
Answer is: n-octane.
Octane is the straight-chain alkane (an acyclic saturated hydrocarbon) with eight carbon atoms.
Carbons in octane have sp3 hybridization (carbon’s 2s and three 2p orbitals combine into four identical sp3 orbitals).
Orbitals in sp3 hybridization have a tetrahedral arrangement and form single (sigma) bonds.
Burning octane fuel is very fast chemical reaction, it happens in immediately.
Main products of the combustion of fossil fuels are carbon(IV) oxide and water.
Chemical reaction: C₈H₁₈ + 25/2O₂ → 8CO₂ + 9H₂O; ΔH = -5500 kJ/mol.
Correct compound is [Co(H2O)6]^+3
The oxidation state of Co is +3
[Co(H2O)6]^+3
Let
Co be x
H2O = 0
x + (0)6 = 3
x = 3
What is oxidation state?
The oxidation state, commonly known as the oxidation number, is the potential charge that an atom would have if all of its bonds to other atoms were fully ionic. It describes the degree of atom oxidation within a chemical compound.The oxidation state may be positive, negative, or zero in theory.
The oxidation number, sometimes referred to as the oxidation state, is the total number of electrons that an atom gains or loses while uniting with another atom to form a chemical bond.
To learn more about oxidation state click the given link
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