All categories

2 years ago

Atoms have a blank shape. the blank of an atom is made up of

Chemistry

2 answers:

timurjin [86]2 years ago

7 0

Answer:

The atom has spherical shape. The nucleus of an atom is made up of protons and neutrons.

Explanation:

The shape of an atom depend upon many factors including angular momentum of electrons and electrostatic forces between particles. So mostly the shape of an atom is complex , however in simplest of atoms have spherical shapes.
The atom consist of three fundamental particle like protons, neutron and electrons. Proton and neutron are collectively form the nucleus of an atom while electrons revolve around the nucleus.

vodka [1.7K]2 years ago

4 0

complete question:

Atoms have a blank shape. The nucleus of an atom is made up of blank that have a positive charge and blank that have no blank.

Answer:

Atoms have a spherical shape. The nucleus of an atom is made up of proton that have a positive charge and neutron that have no charge. The

Explanation:

Atoms are the fundamental unit of matter that defines the structure of an element. Atoms are the basic unit that makes up an element. Atom consist of proton, neutron and electron.

The atom is regarded as been spherical in shape but it has no defined edges. The nucleus of an atom is where the proton and the neutron of an atom resides. The electron is found at the outer part of an atom. It is known to revolve around the atom.

The proton of an atom is positively charged while the neutron has no charge. The proton and the neutron of an atom contributes immensely to the mass of an atom. In fact it determines the mass of an atom.

You might be interested in

When is an atom least likely to react

KonstantinChe [14]

When the atom is stable

4 0

2 years ago

Read 2 more answers

Write an informal definition of half-life.

Pavel [41]

the time required for the activity of a substance taken into the body to lose one half its initial effectiveness. Informal. a brief period during which something flourishes before dying out.

hope this helps ^^

6 0

2 years ago

True or False - when setting up your conversion problems every numerical value must have a unit on it.

Anastaziya [24]

I think its true but im not 100 percent sure

3 0

2 years ago

Differentiate between Physical and chemical changes

Marina CMI [18]

Answer:

In a physical change the appearance or form of the matter changes but the kind of matter in the substance does not. However in a chemical change, the kind of matter changes and at least one new substance with new properties is formed.

<h3> I HOPE THIS WILL HELP YOU IF NOT THEN SORRY HAVE A GREAT DAY:)</h3>

5 0

3 years ago

Read 2 more answers

Combine the two half-reactions that give the spontaneous cell reaction with the smallest E∘. Fe2+(aq)+2e−→Fe(s) E∘=−0.45V I2(s)+

Iteru [2.4K]

Answer: The spontaneous cell reaction having smallest $E^o$ is $I_2+Cu\rightarrow Cu^{2+}+2I^-$

Explanation:

We are given:

$E^o_{(Fe^{2+}/Fe)}=-0.45V\\E^o_{(I_2/I^-)}=0.54V\\E^o_{(Cu^{2+}/Cu)}=0.34V$

The substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction. Here, iodine will always undergo reduction reaction, then copper and then iron.

The equation used to calculate electrode potential of the cell is:

$E^o_{cell}=E^o_{oxidation}+E^o_{reduction}$

The combination of the cell reactions follows:

Case 1:

Here, iodine is getting reduced and iron is getting oxidized.

The cell equation follows:

$I_2(s)+Fe(s)\rightarrow Fe^{2+}(aq.)+2I^-(aq.)$

Oxidation half reaction: $Fe(s)\rightarrow Fe^{2+}(aq.)+2e^-$ $E^o_{oxidation}=0.45V$

Reduction half reaction: $I_2(s)+2e^-\rightarrow 2I_-(aq.)$ $E^o_{reduction}=0.54V$

$E^o_{cell}=0.45+0.54=0.99V$

Thus, this cell will not give the spontaneous cell reaction with smallest $E^o_{cell}$

Case 2:

Here, iodine is getting reduced and copper is getting oxidized.

The cell equation follows:

$I_2(s)+Cu(s)\rightarrow Cu^{2+}(aq.)+2I^-(aq.)$

Oxidation half reaction: $Cu(s)\rightarrow Cu^{2+}(aq.)+2e^-$ $E^o_{oxidation}=-0.34V$

Reduction half reaction: $I_2(s)+2e^-\rightarrow 2I_-(aq.)$ $E^o_{reduction}=0.54V$

$E^o_{cell}=-0.34+0.54=0.20V$

Thus, this cell will give the spontaneous cell reaction with smallest $E^o_{cell}$

Case 3:

Here, copper is getting reduced and iron is getting oxidized.

The cell equation follows:

$Cu^{2+}(aq.)+Fe(s)\rightarrow Fe^{2+}(aq.)+Cu(s)$

Oxidation half reaction: $Fe(s)\rightarrow Fe^{2+}(aq.)+2e^-$ $E^o_{oxidation}=0.45V$

Reduction half reaction: $Cu^{2+}(aq.)+2e^-\rightarrow Cu(s)$ $E^o_{reduction}=0.34V$

$E^o_{cell}=0.45+0.34=0.79V$

Thus, this cell will not give the spontaneous cell reaction with smallest $E^o_{cell}$

Hence, the spontaneous cell reaction having smallest $E^o$ is $I_2+Cu\rightarrow Cu^{2+}+2I^-$

7 0

3 years ago