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Anarel [89]
2 years ago
9

The total charge of an atom comes from

Chemistry
1 answer:
Rus_ich [418]2 years ago
7 0

The total charge on an atom comes from protons and electrons.

The proton is positively charged while the electron is negatively charged. A neutral atom would have an equal number of protons and electrons.

An atom with more protons than electrons will be positively charged while those with more electrons than protons will be negatively charged.

More on the atom can be found here:  brainly.com/question/1641336

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A ball is thrown straight up into the air with a speed of 13 m/s. If the ball has
nataly862011 [7]

Answer:

The total energy, i.e. sum of kinetic and potential energy, is constant.

i.e. E = KE + PE

Initially, PE = 0 and KE = 1/2 mv^2

At maximum height, velocity=0, thus, KE = 0 and PE = mgh

Since, total energy is constant (KE converts to PE when the ball is rising),

therefore, KE = PE 

or, 1/2 mv^2 = mgh

or, h = v^2 /2g = 13^2 / (2x9.8) = 8.622 m

Hope this helps.

5 0
3 years ago
At 17 °C, a 0.80 mole sample of a gas exerts a pressure of 1.2 atm. What is the volume of the container?
lapo4ka [179]

Answer:

A. 16

Explanation:

7 0
3 years ago
Pls help!!! for 100 points, please only answer if your actually going to help ! A kitten has a mass of 1582 g and accelerates at
lys-0071 [83]

Answer:

2689.4

Explanation:

6 0
2 years ago
if the volume of a gas contracted from 648 mL to 0.15L, what was its final pressure if it started at a pressure of 485 kpa
bija089 [108]

Answer:

2100 kPa

Explanation:

The temperature is constant, so the only variables are pressure and volume.

We can use Boyle’s Law.

p₁V₁ = p₂V₂     Divide both sides of the equation by V₂

p₂ = p₁ × V₁/V₂  

p₁ = 485 kPa; V₁ =              648 mL  

p₂ = ?;            V₂ = 0.15 L = 150 mL      Calculate p₂

p₂ = 485 × 648/150

p₂ = 2100 kPa

4 0
3 years ago
What is the empirical formula for a compound which is composed of 31.9 g of Mg and 27.1 g P?​
ahrayia [7]

Answer:

Answer is on the pic

Explanation:

I hope it's helpful!

3 0
2 years ago
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