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Lena [83]
3 years ago
14

Which reaction type is really part of another type of reaction but treated separately? Explain

Chemistry
1 answer:
Novosadov [1.4K]3 years ago
6 0

Answer:

Oxidation - reduction reaction which is called redox reaction.

Explanation:

The type of reaction that is a part of another type but treated separately is called Oxidation - reduction reaction.

Thus is because they usually involve 2 separate half reactions which are oxidation reactions that involve loss of electrons and then reduction equations which involve gain of electrons.

They are treated separately for example when sodium reacts with chlorine to form sodium chloride.

2Na + Cl2 = 2NaCl

Now, sodium undergoes oxidation by loosing elctrons and it's half reaction is;

2Na → 2Na​^(+) + 2e^(-)

​​Meanwhile chlorine undergoes reduction by gaining electrons and its half reaction is;

Cl2 + 2e^(-) → 2Cl^(-)

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What is the concentration of OH − and pOH in a 0.00066 M solution of Ba ( OH ) 2 at 25 ∘ C? Assume complete dissociation.
Allushta [10]

<u>Answer:</u> The hydroxide ion concentration and pOH of the solution is 1.32\times 10^{-3}M  and 2.88 respectively

<u>Explanation:</u>

We are given:

Concentration of barium hydroxide = 0.00066 M

The chemical equation for the dissociation of barium hydroxide follows:

Ba(OH)_2\rightarrow Ba^{2+}+2OH^-

1 mole of barium hydroxide produces 1 mole of barium ions and 2 moles of hydroxide ions

pOH is defined as the negative logarithm of hydroxide ion concentration present in the solution

To calculate pOH of the solution, we use the equation:

pOH=-\log[OH^-]

We are given:

[OH^-]=(2\times 0.00066)=1.32\times 10^{-3}M

Putting values in above equation, we get:

pOH=-\log(1.32\times 10^{-3})\\\\pOH=2.88

Hence, the hydroxide ion concentration and pOH of the solution is 1.32\times 10^{-3}M  and 2.88 respectively

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Explain the difference between cocl2 6h2o and anhydrous cobalt chloride
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