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DedPeter [7]
3 years ago
11

The density of gold is 19.3 g/cm3. What is this density in the units of lbs/in3? (1 in = 2.54 cm and 1 lb = 453.6 g).

Chemistry
1 answer:
DiKsa [7]3 years ago
7 0

Answer:

\rho =0.697\frac{lb}{in^3}

Explanation:

Hello,

In this case, given that 1 inch equals 2.54 cm and 1 lb equals 453.6 g we apply the following conversion factor in order to compute the required density in lb/in³:

\rho=19.3\frac{g}{cm^3}*\frac{1lb}{453.6g}  *(\frac{2.54cm}{1in} )^3\\\\\rho =0.697\frac{lb}{in^3}

Best regards.

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Answer:

0.164541341 g H2

Explanation:

1) Convert grams to moles by dividing by RMM of Magnesium (24.31g).

  2g Mg * (1 mol Mg / 24.31 g Mg) = 0.082270671 mol of Mg

2) Use the balanced equation's ratio of 1 mol Mg: 1 mol H2.

  0.082270671 mol of Mg = 0.082270671 mol of H2

3) Convert the mol of H2 back into grams by multiplying by H2's RMM (2 g).

  0.082270671 mol of H2 * 2 g H2 = 0.164541341 g H2

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valkas [14]

Answer:

<h3>The answer is 4.15 g/mL</h3>

Explanation:

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density =  \frac{mass}{volume} \\

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