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3 years ago

How do the tension of the cord and the force of gravity affect a pendulum

1 answer:

azamat3 years ago

5 0

The time period of the pendulum is affected by the acceleration due to gravity. The tension does not have any effect on the time period of the pendulum and also the mass of the bob does not effect the time period of the pendulum.

$T = 2 \pi \sqrt{\frac{l}{g}}$

Hence, if the gravity increases then the time period of the pendulum will decreases and it will swing faster.

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An electron is accelerqated in the uniform field betwen two parallel charged oplates. The separation of the plates is 1.20 cm

marysya [2.9K]

Answer:

The speed of electron is $8.7\times10^{6}\ m/s$

Explanation:

Given that,

Separation of the plate = 1.20 cm

Suppose the field is $E=1.80\times10^{4}\ N/C$ .

If the electron is accelerated from rest near the negative plate and passes through a tiny hole in the positive plate.

What the speed does it leave the hole?

We need to calculate the acceleration

Using formula of electric force

$F = qE$

$ma=qE$

$a=\dfrac{qE}{m}$

We need to calculate the speed of electron

Using equation of motion

$v^2=u^2+2as$

$v^2=2as$

Put the value of acceleration in the formula

$v^2=2\times\dfrac{qE}{m}\times s$

Put the value into the formula

$v^2=2\times\dfrac{1.6\times10^{-19}\times1.80\times10^{4}\times1.20\times10^{-2}}{9.11\times10^{-31}}$

$v=\sqrt{2\times\dfrac{1.6\times10^{-19}\times1.80\times10^{4}\times1.20\times10^{-2}}{9.11\times10^{-31}}}$

$v=8.7\times10^{6}\ m/s$

Hence, The speed of electron is $8.7\times10^{6}\ m/s$

7 0

3 years ago

A car is stopped at a red light. When the light turns green, the car accelerates until it reaches a final velocity of 45 m/s. It

tigry1 [53]

Answer:

270 m

Explanation:

We can find the distance travelled by the car by using the following suvat equation:

$s=(\frac{u+v}{2})t$

where

s is the distance travelled

u is the initial velocity

v is the final velocity

t is the time

For the car in this problem,

u = 0

v = 45 m/s

t = 12 s

Substituting into the equation, we find:

$s=(\frac{0+45}{2})(12)=270 m$

8 0

3 years ago

Why are metals sometimes added to gold?

Komok [63]

Because solo gold isn't strong material. But with admixture it's stronger.

7 0

4 years ago

Read 2 more answers

Scientific Inquiry incorporates many scientific methods.<br> A) true<br> B) false

Shtirlitz [24]

True fhfhhj ufg ffgh fdh fhgg f jc fg gt

7 0

4 years ago

Until he was in his seventies, Henri LaMothe excited audiences by belly-flopping from a height of 9 m into 32 cm. of water. Assu

baherus [9]

Answer:

823.46 kgm/s

Explanation:

At 9 m above the water before he jumps, Henri LaMothe has a potential energy change, mgh which equals his kinetic energy 1/2mv² just as he reaches the surface of the water.

So, mgh = 1/2mv²

From here, his velocity just as he reaches the surface of the water is

v = √2gh

h = 9 m and g = 9.8 m/s²

v = √(2 × 9 × 9.8) m/s

v = √176.4 m/s

v₁ = 13.28 m/s

So his velocity just as he reaches the surface of the water is 13.28 m/s.

Now he dives into 32 cm = 0.32 m of water and stops so his final velocity v₂ = 0.

So, if we take the upward direction as positive, his initial momentum at the surface of the water is p₁ = -mv₁. His final momentum is p₂ = mv₂.

His momentum change or impulse, J = p₂ - p₁ = mv₂ - (-mv₁) = mv₂ + mv₁. Since m = Henri LaMothe's mass = 62 kg,

J = (62 × 0 + 62 × 13.28) kgm/s = 0 + 823.46 kgm/s = 823.46 kgm/s

So the magnitude of the impulse J of the water on him is 823.46 kgm/s

6 0

3 years ago