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2 years ago

Draw a simple circuit that lights up a bulb.

Physics

2 answers:

coldgirl [10]2 years ago

5 0

Hope this helps

Ps- U can pick between these two pictures

Please mark as brainliest

BlackZzzverrR [31]2 years ago

4 0

$\: \: \: \: \:$

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An ore car of mass 39000 kg starts from rest and rolls downhill on tracks from a mine. At the end of the tracks, 19 m lower vert

cupoosta [38]

Answer:

The compression in the spring is 5.88 meters.

Explanation:

Given that,

Mass of the car, m = 39000 kg

Height of the car, h = 19 m

Spring constant of the spring, $k=4.2\times 10^5\ N/m$

We need to find the compression in the spring in stopping the ore car. It can be done by balancing loss in gravitational potential energy and the increase in elastic energy. So,

$mgh=\dfrac{1}{2}kx^2$

x is the compression in spring

$x=\sqrt{\dfrac{2mgh}{k}} \\\\x=\sqrt{\dfrac{2\times 39000\times 19\times 9.8}{4.2\times 10^5}} \\\\x=5.88\ m$

So, the compression in the spring is 5.88 meters.

6 0

3 years ago

ou are sitting in your car at rest at a traffic light with a bicyclist at rest next to you in the adjoining bicycle lane. As soo

madam [21]

Till the time car is just adjacent to the bicycle we can say

distance moved by cycle = distance moved by car

Time taken by car to accelerate from rest

$t = \frac{v_f - v_i}{a}$

$t = \frac{49 - 0}{7} = 7 s$

Time taken by cycle to accelerate

$t = \frac{23 - 0}{15} = 1.53 s$

now the distance moved by cycle in time "t"

$d = \frac{23 + 0}{2}*1.53 + 23(t - 1.53)$

distance moved by car in same time

$d = \frac{7t + 0}{2}(t)$

now make them equal

$3.5t^2 = 17.595 - 35.19 + 23t$

$3.5 t^2 - 23t + 17.595 = 0$

$t = 5.68 s$

so cycle will move ahead of car for t = 5.68 s

8 0

3 years ago

Read 2 more answers

6. Sandy adds 3 sugar packets to her tea in order to make it sweeter. She stirs in the sugar and then takes a sip. She notices t

irina1246 [14]

Answer:

C.Supersaturated

Explanation:

There are three types of solution:

SATURATED SOLUTION:

It is the solution that contains maximum amount of solute dissolved in a solution in normal conditions.

UNSATURATED SOLUTION:

It is the solution that contains less than the maximum amount of solute dissolved in a solution in normal conditions. It has space for more solute to be dissolved in it.

SUPERSATURATED SOLUTION:

It contains more than the maximum amount of solute dissolved in it. Such a solution has no capacity to dissolve any more solute under any conditions.

Since the sugar is no more dissolving in the tea and has settled down. Therefore, the solution is:

C.Supersaturated

7 0

3 years ago

What is an independent variable

snow_tiger [21]

Answer:

A variable (often denoted by x ) whose variation does not depend on that of another.

Explanation:

8 0

3 years ago

the half-life of iodine-131 is 8.1 days. how much time had passed if i only have one-fourth of the original sample?

morpeh [17]

Answer:

16.2 days

Explanation:

Find the number of halflives:

1/2 * 1/2 = 1/4 so two halflives have passed

2 * 8.1 days = 16.2 days

8 0

1 year ago

Draw a simple circuit that lights up a bulb. ​

Draw a simple circuit that lights up a bulb.