The boiling point of water is 100°C. So at 101°C, the water is steam. Compute the specific heat first from 101 to 100.
E = mCΔT, where c for steam is 1.996 kJ/kg·°C
E₁ = (0.65 kg)(1.996 kJ/kg·°C)(101 - 100°C) = 1.2974 kJ
Next, let's solve the latent heat when steam turns to liquid. The heat of vaporization of water is 2260 kJ/kg.
E₂ = mHvap = (0.65 kg)(2260 kJ/kg) = 1469 kJ
Lastly, let's solve the energy to bring down the temperature to 51°C. The specific heat of liquid water is 4.187 kJ/kg·°C.
E₃ = (0.65 kg)(4.187 kJ/kg·°C)(100 - 51°C) = 139.36 kJ
Thus,
<em>Total energy = 1.2974 kJ+1469 kJ+139.36 kJ = 1,609.66 kJ</em>
Answer:
Alaska: Hydrokinetic Energy Campbell CR9000X used for in-stream hydrokinetic device evaluation. Marine hydrokinetic energy power generation is an emerging sector in the renewable energy portfolio. Hydrokinetic devices convert the energy of waves, tidal currents, ocean currents or river currents into electrical power.
Explanation:
well there is nothing there and it could be different by diffrent objects, idk
