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Nadya [2.5K]
3 years ago
5

apple newest ipad pro has a storage option of up to 128gb (gigabytes). how many bytes of storage will it have? use a conversion

factor, and provide your answer in standard form and scientific notation
Physics
1 answer:
vovikov84 [41]3 years ago
8 0

Explanation:

Storage offered by iPad pro = 128 gb

1 gigabyte = 1000,000,000 bytes

1 gb = 1\times 10^{9} bytes

128 gb=128\times 10^9 bytes=128\times 10^9 bytes

Standard form = 128,000,000,000 bytes of storage

Scientific notation = 1.28\times 10^{11} \text{bytes of storage}


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20 days, 480 hours

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It is dangerous to stand near the railway leak when train passing by,why?​
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Because a person may be pulled in the direction of the moving train. Thereby causing accident

Explanation:

According to Daniel Bernoulli's theorem, he was widely known as a Mathematician. He stated that due to the higher velocity of a moving train, there is higher kinetic energy in terms of volume around it, while the air pressure between the person and the train becomes lower.

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When measuring espresso for a drink, which instrument would give the<br> greatest precision?
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5 0
3 years ago
A horizontal 745 N merry-go-round of radius
Arturiano [62]

Answer:

The kinetic energy of the merry-goround after 3.62 s is  544J

Explanation:

Given :

Weight w = 745 N

Radius r =  1.45 m

Force =  56.3 N

To Find:

The kinetic energy of the merry-go round after 3.62  = ?

Solution:

Step 1:  Finding the Mass of merry-go-round

m = \frac{ weight}{g}

m = \frac{745}{9.81 }

m = 76.02 kg

Step 2: Finding the Moment of Inertia of solid cylinder

Moment of Inertia of solid cylinder I =0.5 \times m \times r^2

Substituting the values

Moment of Inertia of solid cylinder I  

=>0.5 \times 76.02 \times (1.45)^2

=> 0.5 \times 76.02\times 2.1025

=> 79.91 kg.m^2

Step 3: Finding the Torque applied T

Torque applied T = F \times r

Substituting the values

T = 56.3  \times 1.45

T = 81.635 N.m

 Step 4: Finding the Angular acceleration

Angular acceleration ,\alpha  = \frac{Torque}{Inertia}

Substituting the values,

\alpha  = \frac{81.635}{79.91}

\alpha = 1.021 rad/s^2

 Step 4: Finding the Final angular velocity

Final angular velocity ,\omega = \alpha \times  t

Substituting the values,

\omega = 1.021 \times  3.62

\omega = 3.69 rad/s

Now KE (100% rotational) after 3.62s is:

KE = 0.5 \times I \times \omega^2

KE =0.5 \times 79.91 \times 3.69^2

KE = 544J

6 0
4 years ago
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