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NemiM [27]
3 years ago
15

Choose the sentence that might be found in a personal narrative that correctly uses both a gerund and an infinitive.

Physics
1 answer:
Mumz [18]3 years ago
3 0
Let's start with an infinitive: it has a form "to..." - only sentences C and D have a phrase like this, so we can exclude other options.

Among those, C does not have a gerund, which is a verbal form: "dreaming" has a function of a noun there.

So the correct answer is the remaining one, D.
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a sound pulse emitted underwater reflects off a school of fish and is detected at the same place 0.01 s later. how far away are
andrew-mc [135]
In fresh water sound waves travel at 1497m/s at 25 degrees, I'll assume that's the characteristics of the water.

If it's 0.01s then you need to divide the speed by 100 to get the, 14.97, however it gets there and back in that time so you need to halve it.
<u>7.485m</u>
5 0
3 years ago
A refrigerator is 1.8m tall, lm wide,and 0.8m deep.The center of mass is lm from the bottom, 0.5m from the side, and 0.6m from t
VikaD [51]

Answer:

  F = 520 N

Explanation:

For this exercise the rotational equilibrium equation should be used

          Σ τ = 0

Let's set a reference system with the origin at the back of the refrigerator and the counterclockwise rotation as positive. On the x-axis it is horizontal directed outward, eg the horizontal y-axis directed to the side and the z-axis vertical

Torque is

             τ = F x r

the bold indicate vectors, we analyze each force

the applied force is horizontal along the -x axis, the arm (perpendicular distance) is directed in the z axis,

The weight of the body is the vertical direction of the z-axis, so the arm is on the x-axis

                 -F z + W x = 0

                 F z = W x

                 F =  \frac{x}{z}  W

             

The exercise indicates the point of application of the force z = 1.5 m and the weight is placed in the center of mass of the body x = 0.6 m, we are assuming that the force is applied in the wide center of the refrigerator

let's calculate

                 F = 1300 0.6 / 1.5

                 F = 520 N

5 0
3 years ago
A constant force of 3.2 N to the right acts on a 18.2 kg mass for 0.82 s. (a) Find the final velocity of the mass if it is initi
zheka24 [161]

Explanation:

The given data is as follows.

      F = 3.2 N,      m = 18.2 kg,

      t = 0.82 sec

(a)  Formula for impulse is as follows.

          I = Ft = \Delta P

        Ft = m(v_{f} - v_{i})

or,    v_{f} = \frac{Ft}{m} + v_{i}

Putting the given values into the above formula as follows.

      v_{f} = \frac{Ft}{m} + v_{i}

              = \frac{3.2 \times 0.82}{18.2} + 0

              = 0.144 m/s

Therefore, final velocity of the mass if it is initially at rest is 0.144 m/s.

(b)  When velocity is 1.85 m/s to the left then, final velocity of the mass will be calculated as follows.

           Ft = m(v_{f} - v_{i})

or,      v_{f} = \frac{Ft}{m} + v_{i}

                  = \frac{3.2 \times 0.82 sec}{18.2} - 1.85

                  = -1.705 m/s

Hence, we can conclude that the final velocity of the mass if it is initially moving along the x-axis with a velocity of 1.85 m/s to the left is 1.705 m/s towards the left.

4 0
3 years ago
Read 2 more answers
A star moving away emits each wave farther,stretching them. longer waves are ____.
Snezhnost [94]
I think the answer you're looking for is answer B) Not there. Good luck and hoped it helped!
6 0
3 years ago
For each description, choose the fault it describes. Fault types may be used more than once.
MArishka [77]

Answer;

  • Rock layers are placed under compressional stress:  Reverse Fault
  • Rock layers are placed under tensional stress:  Normal Fault
  • Hanging wall has dropped relative to footwall:  Normal Fault
  • Hanging wall has risen relative to footwall: Reverse faults

Explanation;

A normal fault occurs because two tectonic plates are pulling apart from each other, causing tensional stress. The stress allows gravity to pull the hanging wall downward along the footwall, making a cliff-like formation called a scarp. Thus, if you see the hanging wall has dropped relative to the footwall, it is a normal fault. Normal faults occur at divergent boundaries.

A reverse fault happens at convergent boundaries, where two plates colliding produce compressional stress. As the two plates come together, the pressure causes the hanging wall to move upward along the footwall. These breaks are reverse faults because the hanging wall moves in an opposite, or reverse, direction when compared to a normal fault.

A strike-slip fault occurs when tectonic forces cause rock layers to break apart and move in opposite, parallel directions, causing shear stress. The rock layers in a strike-slip fault move sideways past one another.


3 0
3 years ago
Read 2 more answers
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