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2 years ago

8

Since both HBr and KOH are strong, we expect these reactions to occur fully. You mix 2 moles of HBr with 3 moles of KOH in enoug

h water to make 1 L of solution. What is the pH of your final solution?

1 answer:

AysviL [449]2 years ago

8 0

Answer: pH = 14

Explanation: Please see the attachments below

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Explanation:

The given data is as follows.

P = 3 atm

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$V_{1}$ = 9 L = $9 \times 10^{-3} m^{3}$ (as 1 L = 0.001 $m^{3}$ ),

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As relation between work, pressure and change in volume is as follows.

W = $P \times \Delta V$

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Therefore, putting the given values into the above formula as follows.

W = $P \times (V_{2} - V_{1})$

= $3.03975 \times 10^{5} Pa \times (15 \times 10^{-3} m^{3} - 9 \times 10^{-3} m^{3})$

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$\Delta E$ = Q - W

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= -1023.85 J

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Answer:

Explanation:

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